anonymous
  • anonymous
Summation limit:
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
plzzzz just type the question when you post
anonymous
  • anonymous
|dw:1353736632757:dw|
anonymous
  • anonymous
Well it's better when I draw it out.

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anonymous
  • anonymous
The answer is 8 but I have no idea why. @math>philosophy @satellite73
anonymous
  • anonymous
the answer is 8? i don't think that is right
anonymous
  • anonymous
It shouldn't be 8. Are you still doing Riemann sums?
anonymous
  • anonymous
Well according to maple it's 8.
anonymous
  • anonymous
Then there must be a syntax error
anonymous
  • anonymous
I checked on wolfram too.
anonymous
  • anonymous
oh i am a dope
anonymous
  • anonymous
Let me double check.
anonymous
  • anonymous
the index is \(i\) but the expression is \(\frac{8}{n}\)
anonymous
  • anonymous
Yeah.
anonymous
  • anonymous
oh
anonymous
  • anonymous
so it is a constant
anonymous
  • anonymous
Well I know that but then we have: |dw:1353736967140:dw|
anonymous
  • anonymous
\[\sum_{i=1}^n\frac{8}{n}=\frac{8}{n}+\frac{8}{n}+...+\frac{8}{n}\] where there are \(n\) terms and that gives you 8 for all \(n\)
anonymous
  • anonymous
How? If I said n =1 and then n=2 they aren't the same.
perl
  • perl
sigma of 1 is n , so
anonymous
  • anonymous
Ohh right!!!! I feel like an idiot....
anonymous
  • anonymous
are you summing over \(i\) or over \(n\) ?
anonymous
  • anonymous
Got it! Thanks everyone :) .
anonymous
  • anonymous
ok

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