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anonymous
 3 years ago
Summation limit:
anonymous
 3 years ago
Summation limit:

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0plzzzz just type the question when you post

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1353736632757:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well it's better when I draw it out.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The answer is 8 but I have no idea why. @math>philosophy @satellite73

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the answer is 8? i don't think that is right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It shouldn't be 8. Are you still doing Riemann sums?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well according to maple it's 8.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Then there must be a syntax error

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I checked on wolfram too.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the index is \(i\) but the expression is \(\frac{8}{n}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well I know that but then we have: dw:1353736967140:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{i=1}^n\frac{8}{n}=\frac{8}{n}+\frac{8}{n}+...+\frac{8}{n}\] where there are \(n\) terms and that gives you 8 for all \(n\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0How? If I said n =1 and then n=2 they aren't the same.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ohh right!!!! I feel like an idiot....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0are you summing over \(i\) or over \(n\) ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Got it! Thanks everyone :) .
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