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What is the solution of the system? Use substitution.
x = –2y + 10
–6y = 6x – 6
z = –3x + 10y
 one year ago
 one year ago
What is the solution of the system? Use substitution. x = –2y + 10 –6y = 6x – 6 z = –3x + 10y
 one year ago
 one year ago

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sassyjBest ResponseYou've already chosen the best response.0
A. (6, 12) B. (–12, –6) C. (–6, –12) D. (2, 4)
 one year ago

Aditi_SinghBest ResponseYou've already chosen the best response.0
Solve two at a time.
 one year ago

CallistoBest ResponseYou've already chosen the best response.1
1. Label the three equations x = –2y + 10 (1) –6y = 6x – 6 (2) z = –3x + 10y (3) 2. Sub equation (1) into equation (2). Then solve it, you can get the value of y... Hmm... Are you posting the right question?
 one year ago

sassyjBest ResponseYou've already chosen the best response.0
A. x = 9, y = –8, z = 114 B. x = –8, y = 9, z = 114 C. x = –8, y = 114, z = 9 D. x = 114, y = 9, z = –8
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
yeah, now options are correct....
 one year ago

sassyjBest ResponseYou've already chosen the best response.0
I posted the wrong options now, would it be A?
 one year ago

Aditi_SinghBest ResponseYou've already chosen the best response.0
No, it won't be A ..
 one year ago

Aditi_SinghBest ResponseYou've already chosen the best response.0
What did you get on solving the equations? x,y.z?
 one year ago

CallistoBest ResponseYou've already chosen the best response.1
@sassyj Can you solve the first two equations or do you need help?
 one year ago

sassyjBest ResponseYou've already chosen the best response.0
I dont get any of thiseven reading the textbook
 one year ago

CallistoBest ResponseYou've already chosen the best response.1
x = –2y + 10 (1) –6y = 6x – 6 (2) z = –3x + 10y (3) Sub equation (1) into equation (2), that means when you see x, replace x by –2y + 10. Do you get this part?
 one year ago

CallistoBest ResponseYou've already chosen the best response.1
So, try it. Sub. (1) into (2), what do you get?
 one year ago

CallistoBest ResponseYou've already chosen the best response.1
If you really don't understand how substitution works, I suggest you to watch a short video on Khan Academy first http://www.khanacademy.org/math/algebra/systemsofeqandineq/v/practiceusingsubstitutionforsystems
 one year ago
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