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vivalakoda Group Title

Help with exponents?

  • 2 years ago
  • 2 years ago

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  1. vivalakoda Group Title
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    x\[(x^{4})^{3/5}\]

    • 2 years ago
  2. muhammad9t5 Group Title
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    yes...

    • 2 years ago
  3. vivalakoda Group Title
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    Ignore the first x.

    • 2 years ago
  4. muhammad9t5 Group Title
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    power on power will be multiplied

    • 2 years ago
  5. vivalakoda Group Title
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    I do not understand?

    • 2 years ago
  6. muhammad9t5 Group Title
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    4*3/5=12/5

    • 2 years ago
  7. Australopithecus Group Title
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    Use the rules \[x^3 = x(x)x\] \[(x^3)^3 = (x^3)(x^3)(x^3)\]

    • 2 years ago
  8. Australopithecus Group Title
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    \[(x^3)(x^3) = x^6\]

    • 2 years ago
  9. vivalakoda Group Title
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    I'm confused because my answer choices aren't any thing I am getting, or anything like that. They have square roots

    • 2 years ago
  10. Australopithecus Group Title
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    \[(x^3)^3 = (x^3)(x^3)(x^3) = x^9\] 3*3 = 9 3 + 3 + 3 = 9

    • 2 years ago
  11. Australopithecus Group Title
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    look at my example and think about it

    • 2 years ago
  12. muhammad9t5 Group Title
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    see this (x^2)^2 will x^4 i multiplied 2 with 2 for getting answer.

    • 2 years ago
  13. vivalakoda Group Title
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    I understand that you add the exponents when multiplying exponents

    • 2 years ago
  14. Australopithecus Group Title
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    look at my example though, once you understand why it is true you will be able to solve your answer very easily

    • 2 years ago
  15. muhammad9t5 Group Title
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    yes just multiply exponents.

    • 2 years ago
  16. Australopithecus Group Title
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    do you know how to multiply fractions? \[\frac{3}{4}*5 = \frac{3}{4}(\frac{5}{1 }) = \frac{3*5}{4*1} = \frac{3*5}{4} = \frac{15}{4}\]

    • 2 years ago
  17. vivalakoda Group Title
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    Why are you using 3/4?

    • 2 years ago
  18. Australopithecus Group Title
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    I'm showing you examples of fraction multiplication, I'm not going to solve your problem for you, but I will teach you how to solve it

    • 2 years ago
  19. vivalakoda Group Title
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    I know how to do all of that, though.

    • 2 years ago
  20. Australopithecus Group Title
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    so what is your problem?

    • 2 years ago
  21. Australopithecus Group Title
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    exactly?

    • 2 years ago
  22. vivalakoda Group Title
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    All of the answers I'm getting are far from right. I'm really not sure what exactly I'm doing wrong

    • 2 years ago
  23. Australopithecus Group Title
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    well can you show your work?

    • 2 years ago
  24. Australopithecus Group Title
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    I can look it over for you and tell you where you are going wrong

    • 2 years ago
  25. Australopithecus Group Title
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    there isn't any trick to this problem, when you have \[(x^3)^3 = x^9\] \[(x^2)^{1/2} = x^{2\frac{1}{2}} = x^1 = x\] \[(x^5)^{3} = x^{5*3} = x^{15}\]

    • 2 years ago
  26. Australopithecus Group Title
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    show me the answer you are getting

    • 2 years ago
  27. vivalakoda Group Title
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    \[(x^{4})^{3/5}\] = \[x^{4/1} * ^{3/5}\] = multiplied the fraction, got x^12/5 thenhad to put it ion radical form: \[\sqrt[5]{x}^{12}\]

    • 2 years ago
  28. vivalakoda Group Title
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    in*

    • 2 years ago
  29. vivalakoda Group Title
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    after that i am clueless

    • 2 years ago
  30. Australopithecus Group Title
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    looks right

    • 2 years ago
  31. vivalakoda Group Title
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    I know I'm on the right track. But I don't know what else to do, do I simplify the x^12?

    • 2 years ago
  32. Australopithecus Group Title
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    https://www.wolframalpha.com/input/?i=%28x^4%29^%283%2F5%29

    • 2 years ago
  33. Australopithecus Group Title
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    you cant simplify 12/5

    • 2 years ago
  34. Australopithecus Group Title
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    Email your instructor it is obviously a mistake on the site

    • 2 years ago
  35. Australopithecus Group Title
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    In the future it might help to post the answer you got in the question.

    • 2 years ago
  36. Australopithecus Group Title
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    or you can always use wolframalpha to check your answers :)

    • 2 years ago
  37. vivalakoda Group Title
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    Ok. Thank-you for your time!

    • 2 years ago
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