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Help with exponents?

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Other answers:

power on power will be multiplied
I do not understand?
Use the rules \[x^3 = x(x)x\] \[(x^3)^3 = (x^3)(x^3)(x^3)\]
\[(x^3)(x^3) = x^6\]
I'm confused because my answer choices aren't any thing I am getting, or anything like that. They have square roots
\[(x^3)^3 = (x^3)(x^3)(x^3) = x^9\] 3*3 = 9 3 + 3 + 3 = 9
look at my example and think about it
see this (x^2)^2 will x^4 i multiplied 2 with 2 for getting answer.
I understand that you add the exponents when multiplying exponents
look at my example though, once you understand why it is true you will be able to solve your answer very easily
yes just multiply exponents.
do you know how to multiply fractions? \[\frac{3}{4}*5 = \frac{3}{4}(\frac{5}{1 }) = \frac{3*5}{4*1} = \frac{3*5}{4} = \frac{15}{4}\]
Why are you using 3/4?
I'm showing you examples of fraction multiplication, I'm not going to solve your problem for you, but I will teach you how to solve it
I know how to do all of that, though.
so what is your problem?
All of the answers I'm getting are far from right. I'm really not sure what exactly I'm doing wrong
well can you show your work?
I can look it over for you and tell you where you are going wrong
there isn't any trick to this problem, when you have \[(x^3)^3 = x^9\] \[(x^2)^{1/2} = x^{2\frac{1}{2}} = x^1 = x\] \[(x^5)^{3} = x^{5*3} = x^{15}\]
show me the answer you are getting
\[(x^{4})^{3/5}\] = \[x^{4/1} * ^{3/5}\] = multiplied the fraction, got x^12/5 thenhad to put it ion radical form: \[\sqrt[5]{x}^{12}\]
after that i am clueless
looks right
I know I'm on the right track. But I don't know what else to do, do I simplify the x^12?^4%29^%283%2F5%29
you cant simplify 12/5
Email your instructor it is obviously a mistake on the site
In the future it might help to post the answer you got in the question.
or you can always use wolframalpha to check your answers :)
Ok. Thank-you for your time!

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