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anonymous
 4 years ago
Help with exponents?
anonymous
 4 years ago
Help with exponents?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0power on power will be multiplied

Australopithecus
 4 years ago
Best ResponseYou've already chosen the best response.1Use the rules \[x^3 = x(x)x\] \[(x^3)^3 = (x^3)(x^3)(x^3)\]

Australopithecus
 4 years ago
Best ResponseYou've already chosen the best response.1\[(x^3)(x^3) = x^6\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm confused because my answer choices aren't any thing I am getting, or anything like that. They have square roots

Australopithecus
 4 years ago
Best ResponseYou've already chosen the best response.1\[(x^3)^3 = (x^3)(x^3)(x^3) = x^9\] 3*3 = 9 3 + 3 + 3 = 9

Australopithecus
 4 years ago
Best ResponseYou've already chosen the best response.1look at my example and think about it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0see this (x^2)^2 will x^4 i multiplied 2 with 2 for getting answer.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I understand that you add the exponents when multiplying exponents

Australopithecus
 4 years ago
Best ResponseYou've already chosen the best response.1look at my example though, once you understand why it is true you will be able to solve your answer very easily

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes just multiply exponents.

Australopithecus
 4 years ago
Best ResponseYou've already chosen the best response.1do you know how to multiply fractions? \[\frac{3}{4}*5 = \frac{3}{4}(\frac{5}{1 }) = \frac{3*5}{4*1} = \frac{3*5}{4} = \frac{15}{4}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Why are you using 3/4?

Australopithecus
 4 years ago
Best ResponseYou've already chosen the best response.1I'm showing you examples of fraction multiplication, I'm not going to solve your problem for you, but I will teach you how to solve it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I know how to do all of that, though.

Australopithecus
 4 years ago
Best ResponseYou've already chosen the best response.1so what is your problem?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0All of the answers I'm getting are far from right. I'm really not sure what exactly I'm doing wrong

Australopithecus
 4 years ago
Best ResponseYou've already chosen the best response.1well can you show your work?

Australopithecus
 4 years ago
Best ResponseYou've already chosen the best response.1I can look it over for you and tell you where you are going wrong

Australopithecus
 4 years ago
Best ResponseYou've already chosen the best response.1there isn't any trick to this problem, when you have \[(x^3)^3 = x^9\] \[(x^2)^{1/2} = x^{2\frac{1}{2}} = x^1 = x\] \[(x^5)^{3} = x^{5*3} = x^{15}\]

Australopithecus
 4 years ago
Best ResponseYou've already chosen the best response.1show me the answer you are getting

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[(x^{4})^{3/5}\] = \[x^{4/1} * ^{3/5}\] = multiplied the fraction, got x^12/5 thenhad to put it ion radical form: \[\sqrt[5]{x}^{12}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0after that i am clueless

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I know I'm on the right track. But I don't know what else to do, do I simplify the x^12?

Australopithecus
 4 years ago
Best ResponseYou've already chosen the best response.1you cant simplify 12/5

Australopithecus
 4 years ago
Best ResponseYou've already chosen the best response.1Email your instructor it is obviously a mistake on the site

Australopithecus
 4 years ago
Best ResponseYou've already chosen the best response.1In the future it might help to post the answer you got in the question.

Australopithecus
 4 years ago
Best ResponseYou've already chosen the best response.1or you can always use wolframalpha to check your answers :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok. Thankyou for your time!
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