amistre64
  • amistre64
Let n=\(2^3*3^2*5*7^3*11\) Find the smallest factorial: k! that is divisible by n Show your work!! :)
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
27!
amistre64
  • amistre64
thats not work, thats an answer .... teaches me nothing :/
hba
  • hba
I thought this was open study.

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More answers

anonymous
  • anonymous
=2^3*3^13*5*7 here 13 is the maximum power raised on any number. thus we have to take till the number untill 3 comes 13 times 3=1 6=1 9=2 12=1 15=1 18=2 21=2 24=2 27=3 Total of rhs=15>13 thus 27! will be the ans
amistre64
  • amistre64
------------------ 2 2 2 3 3 5 7 7 7 11 2 ------------------ 1 2 2 3 3 5 7 7 7 11 2 3 ------------------ 2 2 3 5 7 7 7 11 2 3 4 ------------------ 3 5 7 7 7 11 2 3 4 5 ------------------ 3 7 7 7 11 2 3 4 5 6 ------------------ 7 7 7 11 2 3 4 5 6 7 ------------------ 7 7 11 2 3 4 5 6 7 8 9 10 11 ------------------ 7 7 2 3 4 5 6 7 8 9 10 11 12 13 14 ---------------------------- 7 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 ----------------------------------------------- i think its 21!
amistre64
  • amistre64
you seem to have used something different than that i posted in the question
amistre64
  • amistre64
does your method, using my posted information, equate to 27 as well? or is it 21?
asnaseer
  • asnaseer
yup - I also get 21 using the same method as @amistre64
amistre64
  • amistre64
im pretty adept at brute mathing; i see some potential in Malachys if i can get it verified ;)
asnaseer
  • asnaseer
I have never heard of Malachys - oh well - another new topic to learn...
asnaseer
  • asnaseer
do you have a reference (a link) to this method?
amistre64
  • amistre64
i see in mine the 7^3 produces the biggest parts; and 7*3 = 21
amistre64
  • amistre64
my method? i thought it up
asnaseer
  • asnaseer
true - but still have to show that all numbers before this are factored out as well - which you did using brute force :)
asnaseer
  • asnaseer
you said " i see some potential in Malachys" <<<--- is this made up? :)
amistre64
  • amistre64
lol, we may never know unless they show up again ;)
asnaseer
  • asnaseer
you jest with us mere mortals sir! :)
amistre64
  • amistre64
=2^3*3^2*5*7^3*11 here 3 is the maximum power raised on any number. thus we have to take till the number untill (2 or 7 ???) comes 3 times ???? Total of rhs=??? thus 21! will be the ans seems simple enough to me
anonymous
  • anonymous
Actually i was missed as 2^3*3^2*5*7*3^11 thats why that ans came
amistre64
  • amistre64
can you give a generalized rule for your method?

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