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lilsis76
 3 years ago
How can I rewrite the sum's suing Sigma Notation for:
2  2^2 + 2^3 2^4 +2^5
I know the reoccuring number is going to be 2 which goes to the right of the sigma. on the bottom of sigma it would be 1, and top of sigma would be 5 right?
lilsis76
 3 years ago
How can I rewrite the sum's suing Sigma Notation for: 2  2^2 + 2^3 2^4 +2^5 I know the reoccuring number is going to be 2 which goes to the right of the sigma. on the bottom of sigma it would be 1, and top of sigma would be 5 right?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{n=0}^{4}2(2)^n\] is one way of writing it.

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0oh. so that (2), is that how it would go from negative to positive?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0expand what i wrote and check for yourself

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0okay: 2^0 = 0 *2 = 0 2^1=2*2=4 2^2=4*2=8 2^3=8*2=16

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0@cnknd is this how it would go?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ur doing the exponents wrong... this is basics...

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1353786706417:dwokay the first one would be>....< @cnknd

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0in what i put down, the index n goes from 0 to 4... so it's 2(2)^0 + 2(2)^1 + 2(2)^2 + 2(2)^3 + 2(2)^4 which is 2(1) + 2(2) + 2(4) + 2(8) + 2(16)

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0OH SHOOT! i just noticed i started at 1. i just now noticed it starts at 0

lilsis76
 3 years ago
Best ResponseYou've already chosen the best response.0okay okay, i got it now. it makes more sense starting at zero haha thank you. Medal for you :)
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