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samalami
 2 years ago
Pre Calc:
If y varies inversely as the cube root of x, and y = 12 when x = 8, find y when x = 1.
y = ?
xoxo
samalami
 2 years ago
Pre Calc: If y varies inversely as the cube root of x, and y = 12 when x = 8, find y when x = 1. y = ? xoxo

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Jonask
 2 years ago
Best ResponseYou've already chosen the best response.0\[y=\frac{k}{x^3}\] put(8,12) then find k

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.0after since you have k put x=1 to get y

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1cube ROOT of x, might wanna fix that real quick @Jonask ! :D

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.0yes\[y=\frac{ k }{\sqrt[3]{x} }\] thanks @zepdrix

samalami
 2 years ago
Best ResponseYou've already chosen the best response.1Ifound 12=k/8^3 (y=k/x^3 with substitutions) ~12=1644/8^3

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.0@samalami the formular had mistake

samalami
 2 years ago
Best ResponseYou've already chosen the best response.1thanks for the clarification @zepdrix :)

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1k=24? yah that sounds right :D

Jonask
 2 years ago
Best ResponseYou've already chosen the best response.0so now find y when x=1\[y=\frac{24}{\sqrt[3]{1}}\]

samalami
 2 years ago
Best ResponseYou've already chosen the best response.1y would equal 24 @Jonask

samalami
 2 years ago
Best ResponseYou've already chosen the best response.1@zepdrix does this mean y=24 is the answer to the entire question?

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Hmm yah that sounds right :D Yayyy sammy! \c:/

samalami
 2 years ago
Best ResponseYou've already chosen the best response.1@zepdrix much thanks! xoxo
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