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Pre Calc:
If y varies inversely as the cube root of x, and y = 12 when x = 8, find y when x = 1.
y = ?
xoxo
 one year ago
 one year ago
Pre Calc: If y varies inversely as the cube root of x, and y = 12 when x = 8, find y when x = 1. y = ? xoxo
 one year ago
 one year ago

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JonaskBest ResponseYou've already chosen the best response.0
\[y=\frac{k}{x^3}\] put(8,12) then find k
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
after since you have k put x=1 to get y
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
cube ROOT of x, might wanna fix that real quick @Jonask ! :D
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
yes\[y=\frac{ k }{\sqrt[3]{x} }\] thanks @zepdrix
 one year ago

samalamiBest ResponseYou've already chosen the best response.1
Ifound 12=k/8^3 (y=k/x^3 with substitutions) ~12=1644/8^3
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
@samalami the formular had mistake
 one year ago

samalamiBest ResponseYou've already chosen the best response.1
thanks for the clarification @zepdrix :)
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
k=24? yah that sounds right :D
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
so now find y when x=1\[y=\frac{24}{\sqrt[3]{1}}\]
 one year ago

samalamiBest ResponseYou've already chosen the best response.1
y would equal 24 @Jonask
 one year ago

samalamiBest ResponseYou've already chosen the best response.1
@zepdrix does this mean y=24 is the answer to the entire question?
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Hmm yah that sounds right :D Yayyy sammy! \c:/
 one year ago

samalamiBest ResponseYou've already chosen the best response.1
@zepdrix much thanks! xoxo
 one year ago
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