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answer choices A,B,C,D from top to bottom :)

idk how to simplify this :(

first use\[(a^b)^c=a^{bc}\]

1st 1
\[(a^6b^3c^3)^5=a^{6(5)}b^{3(5)}c^{3(5)}\]

okay so i get a^11b^15c^15??

do 4 the next two brackets the same thing

kk was what i got right?

yes

second one= a^-15b^6 ??

yes

and last one= b^-3c^-9 ?

I have a problem with 1st 1
5(6)=30

\[a^{30}b^{15}c^{15}\]

oh oops!! haha my bad i added by accident lol so yeah 30... how do i combine them now?

yeah hahah there we go :) thats better :)

so now you add all the power that have the same base\[a^ca^d=a^{c+d}\]

yes just group them next to each other 1st

(a^30b^15c^15)( a^-15b^6) (b^-3c^-9) ?? thats right yes?

a^(30-15)b^(15+6-3)c^(15-(-9))

kk so i get a^15b^18c^24 ??

yes

but thats not an answer chose... which is my answe then?

here are the answer choices again so u don't need to scroll up :)
A,B,C,D from top to bottom :)

c^(15-9)=c^6

so its a^15b^18c^6

so answer D? :)