Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Simplify the expression attached!

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

answer choices A,B,C,D from top to bottom :)
idk how to simplify this :(

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

first use\[(a^b)^c=a^{bc}\]
okay but idk how to apply that here :( I'm kinda confused :( can u pls show me and explain how u got it too? :)
just write the powers outside the brackets on top of every number inside in multiplication form as the rule above
1st 1 \[(a^6b^3c^3)^5=a^{6(5)}b^{3(5)}c^{3(5)}\]
okay so i get a^11b^15c^15??
do 4 the next two brackets the same thing
kk was what i got right?
yes
second one= a^-15b^6 ??
yes
and last one= b^-3c^-9 ?
I have a problem with 1st 1 5(6)=30
\[a^{30}b^{15}c^{15}\]
oh oops!! haha my bad i added by accident lol so yeah 30... how do i combine them now?
yeah hahah there we go :) thats better :)
so now you add all the power that have the same base\[a^ca^d=a^{c+d}\]
do u think u can write all the sums we got for all 3 brackets like u did above?? cuz when i write it like this it gets all jumbled up and idk how to write it like u did above... all nice and stuff haha :P
yes just group them next to each other 1st
(a^30b^15c^15)( a^-15b^6) (b^-3c^-9) ?? thats right yes?
a^(30-15)b^(15+6-3)c^(15-(-9))
kk so i get a^15b^18c^24 ??
yes
but thats not an answer chose... which is my answe then?
here are the answer choices again so u don't need to scroll up :) A,B,C,D from top to bottom :)
so which one is it then? @Jonask :)
c^(15-9)=c^6
so its a^15b^18c^6
so answer D? :)
@Jonask nvm i found it ahha :P it is D :) thanks!

Not the answer you are looking for?

Search for more explanations.

Ask your own question