A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
i must find lim of a_n for x_n = 1/n( 1/ln(2) + ... + 1/ln(n) ) using stoltz cesaro theorem
anonymous
 3 years ago
i must find lim of a_n for x_n = 1/n( 1/ln(2) + ... + 1/ln(n) ) using stoltz cesaro theorem

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0xn>int 1/xlnx]1 to inf=ln(lnx)]1 to inf=inf so limxn=inf

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0(1/n)*( 1/ln(2) + ... + 1/ln(n) ) is the equation sorry

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I must use stoltz cesaro \[\frac{a_{n+1}a ^{n} }{ b_{n+1}b ^{n} }\] for \[x _{n}=\frac{ 1 }{ n}*(\frac{ 1 }{ \ln_{2} }+ ... +\frac{ 1 }{ \ln_{n} })\] and i don t know how to find \[a_{n}\] and \[b _{n}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0try b_n = n, and a_n = 1/ln2 + ... + 1/ln(n)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0with n get lim = 0 which is good but can i take only n and not 1/n as b_n? :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I compare with integral which it approach to infinity then I conclude the series is also infinity or it is diverged.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i have a hint and says that the result is 0 but if i consider b_n 1/n the result is infinity so i don't know if the hint is good or not or whick one is correct

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ugh you want x_n in the form of a_n/b_n... so tell me, what would a_n be if b_n = 1/n?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you' re right now i saw that if u write them your way is the same thing, is correct, i understood and the result is 0 as it should be thank you very muc :D i apreciate it
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.