Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

i must find lim of a_n for x_n = 1/n( 1/ln(2) + ... + 1/ln(n) ) using stoltz cesaro theorem

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

xn>int 1/xlnx]1 to inf=ln(lnx)]1 to inf=inf so limxn=inf
(1/n)*( 1/ln(2) + ... + 1/ln(n) ) is the equation sorry
I must use stoltz cesaro \[\frac{a_{n+1}-a ^{n} }{ b_{n+1}-b ^{n} }\] for \[x _{n}=\frac{ 1 }{ n}*(\frac{ 1 }{ \ln_{2} }+ ... +\frac{ 1 }{ \ln_{n} })\] and i don t know how to find \[a_{n}\] and \[b _{n}\]

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Please help
try b_n = n, and a_n = 1/ln2 + ... + 1/ln(n)
b_n is n or 1/n :-S
with n get lim = 0 which is good but can i take only n and not 1/n as b_n? :D
I compare with integral which it approach to infinity then I conclude the series is also infinity or it is diverged.
i have a hint and says that the result is 0 but if i consider b_n 1/n the result is infinity so i don't know if the hint is good or not or whick one is correct
ugh you want x_n in the form of a_n/b_n... so tell me, what would a_n be if b_n = 1/n?
you' re right now i saw that if u write them your way is the same thing, is correct, i understood and the result is 0 as it should be thank you very muc :D i apreciate it

Not the answer you are looking for?

Search for more explanations.

Ask your own question