anonymous
  • anonymous
PLEASEEE help with geo problem :( find the volume of the regular pyramid. https://media.glynlyon.com/g_geo_2012/8/groupi77.gif
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
i got 16 sqrt 2 but its saying its wrong
anonymous
  • anonymous
Well the volume is just the area of the base times height.
anonymous
  • anonymous
well i dont understand how it would be in square root form?

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More answers

nubeer
  • nubeer
did you find the area of base?
anonymous
  • anonymous
isnt it 16
nubeer
  • nubeer
hmm no.. the base is like a triangle.. not square.
anonymous
  • anonymous
well how would you find it ? multiplying length and width?
nubeer
  • nubeer
hmm no.. area of triangle = 1/2 *base *height,
anonymous
  • anonymous
so 8?
nubeer
  • nubeer
yes i think so.. vol of pyramid = 1/3 * area of base * height of pyramid.
anonymous
  • anonymous
so 8 times 4 ? which is 32?
nubeer
  • nubeer
i am not sure if 4 is the height as the diagram is very much titlted.
anonymous
  • anonymous
well what would you think it is? because i can always try it and see if its right or wrong. it gives me another chance. but would it be 32 sqrt 3?
nubeer
  • nubeer
how you got this answer?
anonymous
  • anonymous
32 from the area and 3 because of 1/3 actually im not sure im really confused
nubeer
  • nubeer
hmm no dont think so it should be 32/3 then
anonymous
  • anonymous
okay then what ?
nubeer
  • nubeer
i think this should e the volume of pyramid.
anonymous
  • anonymous
32 sqrt 3?
nubeer
  • nubeer
noo.. how you get square root.. i never get square root.. i got 32/3
anonymous
  • anonymous
well the answer format has this |dw:1353832060046:dw|
nubeer
  • nubeer
hmm then we made some mistake earlier.. i think probably should be height or the area of base.
anonymous
  • anonymous
i dont know what to do :(
nubeer
  • nubeer
hmm ask someone else.
anonymous
  • anonymous
like? ive been asking this for the whole day
nubeer
  • nubeer
just tag people .. ask Hatrn or any other moderator.
anonymous
  • anonymous
ok thanks for your time.

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