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pottersheep
Group Title
I need Trig Identity help please..! (Grade 12)
How do I prove...
(cos2x/1+sin2x) = tan(pi/4 x)
 2 years ago
 2 years ago
pottersheep Group Title
I need Trig Identity help please..! (Grade 12) How do I prove... (cos2x/1+sin2x) = tan(pi/4 x)
 2 years ago
 2 years ago

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tkhunny Group TitleBest ResponseYou've already chosen the best response.1
You have written this: \(\dfrac{\cos(2x)}{1} + \sin(2x) = \tan(\frac{\pi}{4}  x)\). Is this what you intend?
 2 years ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
Ohhhhh you are right my mistake!
 2 years ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
It should be (cos2x/(1+sin2x) = tan(pi/4 x)
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{\cos^2(x)}{1+\sin^2(x)}\]?
 2 years ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
No, They are not to the power of 2, they are just 2x :)
 2 years ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
Well, it certainly looks like an exercise in double angles. Perhaps expanding all three expressions will lead to something.
 2 years ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
im still stuck :(
 2 years ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
I THINK I GOT IT :)
 2 years ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
yay double angles worked~~~!!
 2 years ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
Let's see your work and perhaps we can untangle it. \(\cos(2x) = \cos^{2}(x)  \sin^{2}(x) = 1  2\sin^{2}(x) = 2\cos^{2}(x)  1\) \(\sin(2x) = 2\sin(x)\cos(x)\) You may wish to convert the tangent to sine/cosine. Really, the idea behind these things is to get you to EXPLORE these relationships. Don't expect to see a clear solution right away. Play with it until somthing pops out.
 2 years ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.0
@pottersheep do you need hint?
 2 years ago
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