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pottersheep
Group Title
I need Trig Identity help please..! (Grade 12)
How do I prove...
(cos2x/1+sin2x) = tan(pi/4 x)
 one year ago
 one year ago
pottersheep Group Title
I need Trig Identity help please..! (Grade 12) How do I prove... (cos2x/1+sin2x) = tan(pi/4 x)
 one year ago
 one year ago

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tkhunny Group TitleBest ResponseYou've already chosen the best response.1
You have written this: \(\dfrac{\cos(2x)}{1} + \sin(2x) = \tan(\frac{\pi}{4}  x)\). Is this what you intend?
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
Ohhhhh you are right my mistake!
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
It should be (cos2x/(1+sin2x) = tan(pi/4 x)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{\cos^2(x)}{1+\sin^2(x)}\]?
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
No, They are not to the power of 2, they are just 2x :)
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
Well, it certainly looks like an exercise in double angles. Perhaps expanding all three expressions will lead to something.
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
im still stuck :(
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
I THINK I GOT IT :)
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
yay double angles worked~~~!!
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
Let's see your work and perhaps we can untangle it. \(\cos(2x) = \cos^{2}(x)  \sin^{2}(x) = 1  2\sin^{2}(x) = 2\cos^{2}(x)  1\) \(\sin(2x) = 2\sin(x)\cos(x)\) You may wish to convert the tangent to sine/cosine. Really, the idea behind these things is to get you to EXPLORE these relationships. Don't expect to see a clear solution right away. Play with it until somthing pops out.
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.0
@pottersheep do you need hint?
 one year ago
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