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Simplify the expression attached and write it as a single logarithm..
***still confused on this topic... pls help? :)
 one year ago
 one year ago
Simplify the expression attached and write it as a single logarithm.. ***still confused on this topic... pls help? :)
 one year ago
 one year ago

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iheartfoodBest ResponseYou've already chosen the best response.1
answer choices A,B,C,D from top to bottom :)
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
Move all the exponents up: \((x+4)^{3}\) \((x7)^{2}\) \((x2)^{5}\) \((x^{2})^{1}\) Notice how I deliberately left everything outside as ADDITION. This allows us just to bring everything inside without concern for numerator or denominator. We can figure all that out later.
 one year ago

iheartfoodBest ResponseYou've already chosen the best response.1
im confused.. so how can i apply that with my expression?
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
Confused with what? \(3\log(x+4) = \log\left[\left(x+4\right)^{3}\right]\) Correct?
 one year ago

iheartfoodBest ResponseYou've already chosen the best response.1
im not quite sure what we are working on now.. I'm like uber confused.. are we doing my problem? or an example? :/ sorry I'm a bit confused :(
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
Your problem statement begins \(3\log(x+4)\), doesn't it? Or am I looking at some other picture?
 one year ago

iheartfoodBest ResponseYou've already chosen the best response.1
yup iy does :) so i get log[(x+4)^−3] from that part?
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
Very good. Now the (x7) part?
 one year ago

iheartfoodBest ResponseYou've already chosen the best response.1
2log(x7) = log(x7)^2 ??
 one year ago

iheartfoodBest ResponseYou've already chosen the best response.1
5log(x2)=log(x2)^5 ??
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
One more. You're on a roll!
 one year ago

iheartfoodBest ResponseYou've already chosen the best response.1
lol thanks haha :P but i don't get this one... it looks different.. :/ logx^2...
 one year ago

iheartfoodBest ResponseYou've already chosen the best response.1
but heres my take on it.. log(x^2)^1 ??
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
Take the negative (1) inside, just like the other coefficients ==> exponents.
 one year ago

iheartfoodBest ResponseYou've already chosen the best response.1
was what i got right?? or no?
 one year ago

iheartfoodBest ResponseYou've already chosen the best response.1
or is it log(x)^2 ?
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
There it is. They are now all connected by addition. Use this guy and bring them all together. log(a) + log(b) = log(a*b)
 one year ago

iheartfoodBest ResponseYou've already chosen the best response.1
sorry my computer crashed... one sec :/
 one year ago

iheartfoodBest ResponseYou've already chosen the best response.1
log[(x+4)^−3]+ log(x2)^5+log(x7)^2 + log(x)^2=answer B right? :)
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
use the rule described above to go from log[(x+4)^−3]+ log(x2)^5+log(x7)^2 + log(x)^2 to log[ (x+4)^−3*(x2)^5*(x7)^2*(x)^2 ]
 one year ago

iheartfoodBest ResponseYou've already chosen the best response.1
kk I'm seeing that :) but how can i simplify it even further?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
(x+4)^−3 is really 1/[ (x+4)^3 ]
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
same idea applies to (x)^2
 one year ago

iheartfoodBest ResponseYou've already chosen the best response.1
ok so i get 1/x^2 ?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
so put that all together
 one year ago

iheartfoodBest ResponseYou've already chosen the best response.1
so i get answer C right?? :)
 one year ago

iheartfoodBest ResponseYou've already chosen the best response.1
sorry i meant answer D :) is it answer D then? :)
 one year ago

iheartfoodBest ResponseYou've already chosen the best response.1
@jim_thompson5910 :)
 one year ago
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