At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

answer choices A,B,C,D from top to bottom :)

im confused.. so how can i apply that with my expression?

Confused with what? \(-3\log(x+4) = \log\left[\left(x+4\right)^{-3}\right]\) Correct?

Your problem statement begins \(-3\log(x+4)\), doesn't it? Or am I looking at some other picture?

yup iy does :) so i get log[(x+4)^−3] from that part?

Very good. Now the (x-7) part?

2log(x-7) = log(x-7)^2 ??

Good, now the x-2...

5log(x-2)=log(x-2)^5 ??

One more. You're on a roll!

lol thanks haha :P but i don't get this one... it looks different.. :/
-logx^2...

but heres my take on it..
log(x^2)^-1 ??

Take the negative (-1) inside, just like the other coefficients ==> exponents.

was what i got right?? or no?

or is it log(x)^-2 ?

sorry my computer crashed... one sec :/

log[(x+4)^−3]+ log(x-2)^5+log(x-7)^2 + log(x)^-2=answer B right? :)

kk I'm seeing that :) but how can i simplify it even further?

(x+4)^−3 is really 1/[ (x+4)^3 ]

same idea applies to (x)^-2

ok so i get 1/x^-2 ?

yep

so put that all together

so i get answer C right?? :)

sorry i meant answer D :) is it answer D then? :)

yes it is D

kk great!!! thx :)