anonymous
  • anonymous
Simplify the expression!! :)
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1353809728543:dw|
anonymous
  • anonymous
A. 5e/2 B. 5/x2 C. 10ex D. 5 - 2 ln(x)
anonymous
  • anonymous
here are the formulas u can use: ln(A*B) = ln(A) + ln(B) ln(A/B) = ln(A) - ln(B)

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anonymous
  • anonymous
Don't forget: \[ \ln(a^b)=b\ln(a) \]And: \[ \ln(e)=1 \]
anonymous
  • anonymous
k so i have to rearrange it right?
anonymous
  • anonymous
Try using those rules.
anonymous
  • anonymous
im not quite sure how.. can u pls show me?
anonymous
  • anonymous
Use this one first. ln(A/B) = ln(A) - ln(B)
anonymous
  • anonymous
k but how do i plug them in?? i have a hard time figuring out what to plug into where..
anonymous
  • anonymous
|dw:1353811209406:dw|
anonymous
  • anonymous
|dw:1353811258993:dw| is that it?
anonymous
  • anonymous
Ok, now use this: ln(a^b)=b*ln(a)
anonymous
  • anonymous
|dw:1353811431501:dw| is that right?
anonymous
  • anonymous
I'm not sure what that is. Here's how I see it. |dw:1353811722405:dw|
anonymous
  • anonymous
kk :) following:)
anonymous
  • anonymous
Do you see how that matches the pattern of ln(a^b)=b*ln(a) ?
anonymous
  • anonymous
yeah :) so what do i do next? :)
anonymous
  • anonymous
Last is to use this: ln(e)=1
anonymous
  • anonymous
do i get this? 5-2ln(x) ??
anonymous
  • anonymous
anonymous
  • anonymous
I think u got it corrct 5-2ln(x)
anonymous
  • anonymous
are u sure?? based on what @CliffSedge said, it leads to my answer being D. 5-2ln(x) ??
anonymous
  • anonymous
anonymous
  • anonymous
Yeah D. Is correct one. Im quite sure:)
anonymous
  • anonymous
kk thank you :)
anonymous
  • anonymous
You r wlcm! Pretty much you got iy yourself:)

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