iheartfood
Simplify the expression!! :)



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iheartfood
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dw:1353809728543:dw

iheartfood
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A. 5e/2
B. 5/x2
C. 10ex
D. 5  2 ln(x)

cnknd
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here are the formulas u can use:
ln(A*B) = ln(A) + ln(B)
ln(A/B) = ln(A)  ln(B)

LolWolf
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Don't forget:
\[
\ln(a^b)=b\ln(a)
\]And:
\[
\ln(e)=1
\]

iheartfood
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k so i have to rearrange it right?

LolWolf
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Try using those rules.

iheartfood
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im not quite sure how.. can u pls show me?

CliffSedge
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Use this one first. ln(A/B) = ln(A)  ln(B)

iheartfood
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k but how do i plug them in?? i have a hard time figuring out what to plug into where..

CliffSedge
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dw:1353811209406:dw

iheartfood
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dw:1353811258993:dw is that it?

CliffSedge
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Ok, now use this: ln(a^b)=b*ln(a)

iheartfood
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dw:1353811431501:dw is that right?

CliffSedge
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I'm not sure what that is. Here's how I see it.
dw:1353811722405:dw

iheartfood
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kk :) following:)

CliffSedge
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Do you see how that matches the pattern of ln(a^b)=b*ln(a) ?

iheartfood
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yeah :) so what do i do next? :)

CliffSedge
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Last is to use this: ln(e)=1

iheartfood
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do i get this? 52ln(x) ??

iheartfood
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@CliffSedge ?

ktnguyen1
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I think u got it corrct 52ln(x)

iheartfood
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are u sure?? based on what @CliffSedge said, it leads to my answer being D. 52ln(x) ??

iheartfood
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@ktnguyen1 ? :)

ktnguyen1
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Yeah D. Is correct one. Im quite sure:)

iheartfood
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kk thank you :)

ktnguyen1
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You r wlcm! Pretty much you got iy yourself:)