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Is the 'del' symbolic of using the delta function?

Absolutely yes.

In my textbook, the delta function is not introduced for 4 more sections.

Do you know extended derivative with delta function?

Mathematician said there is no derivative in uncontinious point but engineers said it has.

So far what I know of piecewise functions is that L{f(x)} = L{f_1(x)} + L{f_2(x)} + L{f_3(x)}

Those should be f(t)...

How did you make a derivative of a function that has only a constant value?

L(f(t))=L(1)=1/s
if for f(t)=t then
L(f(t))=1/s^2

mohan gholami in which of them?

If it never equals 't', then do I only have
\[\frac{1}{s} +\frac{1}{s} +\frac{1}{s}\] ?

I believe he was saying that you were an engineer.

No, you have two points not two functions!

Unfortunately Laplace transform doesn't sense points unless with delta function.

L(f(t))=L(3)=3L(1)=3*1/s=3/s

can we take laplace inverse at the end?

So you would have: L{f(t)} = L{1} + L{3} + L{4} -> 1/s + 0 + 0 ?

ok I solve it with integral.
int(0 inf) f(t)=1/s

You know the integral change the limit points to continues function and never sense them.

I thought in two points 1 and 2 it has jumped so they were two alone points.

And Laplace has problem with the single points.

Ah. Okay, I will see if I can't apply this to the rest of my problems. Thank you very much.

You're welcome.

L{f(t)} = L{1} + L{3} + L{4} -> 1/s + 0 + 0=1/s

Okay.

Alright, I'll have to look up limit points then because I have not seen them yet as I recall.