Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

-4sqrt(x+9)=20 can anyone help?

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

\[-4 \sqrt{(x+9)} = 20\] Like this? At what part are you getting stuck?
well i get x=16 but when i try to see if its true i get -20=20
and yes like that

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Yeah, with that -4 outside the square root, I think it's undefined.
yeah your probably right. extraneous solution?
If we defined \(y\) as \(\sqrt{(x+9)}\), we would get \(-4y = 20\), with \(y = -5\), and there is no way \(\sqrt{(x+9)} = -5\)
hmmm i dont know. but when we divide -4 we get \[\sqrt{x+9}=-5\]
\(\large{\sqrt{-x} = i \sqrt{x}}\) right?
Okay, can we use that somehow?
Oh wait... We can square both sides, right?
hmmm yeah
and we get x+9=25 because -5x-5=25
Right, so you were right with 16; it is an extraneous root.
yeah it looks like that then and thanks man
Hey, no problem. :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question