A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

iheartfood
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1353813925701:dw

iheartfood
 2 years ago
Best ResponseYou've already chosen the best response.0A. 16 years B. 54 years C. 2.4 years D. 9 years

tkhunny
 2 years ago
Best ResponseYou've already chosen the best response.1\(0.29\cdot(1.046)^{t} = 0.60\) Solve for 't'. You will need logarithms.

tkhunny
 2 years ago
Best ResponseYou've already chosen the best response.1Introduce the logarithm \(\log\left(0.29\cdot(1.046)^{t}\right) = \log(0.60)\) Now what?

iheartfood
 2 years ago
Best ResponseYou've already chosen the best response.0idk.. but i think the answer is A. 16 years.. is that right?

tkhunny
 2 years ago
Best ResponseYou've already chosen the best response.1"I think the answer is..." is not ever an acceptable response. In mathematics, you must prove it. Use the logarithm rules. There is a reason why we did that massive problem, before. \(\log(0.29) + t\cdot\log(1.046) = \log(0.60)\) You need to see where ALL of this came from.

iheartfood
 2 years ago
Best ResponseYou've already chosen the best response.0kk so what do i do now then?

tkhunny
 2 years ago
Best ResponseYou've already chosen the best response.1Solve for 't'. You must be able to do this. This is why we invented notation. It will help you. Use the notation, and proper operations on that notation, to solve for 't'. Let's see what you get.

tkhunny
 2 years ago
Best ResponseYou've already chosen the best response.1Are you going to show us any work?
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.