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tkhunnyBest ResponseYou've already chosen the best response.1
Just like you used to solve polynomials back in algebra. Collecte everything to one side. Factor everything. Give it a go!
 one year ago

cnkndBest ResponseYou've already chosen the best response.1
lol dont need to go that far. let x = tan(theta), then 3x^3 = x, so either x = 0, or you can divide x from both sides to get: 3x^2 = 1 so x can be 0, 1/sqrt(3), or 1/sqrt(3).
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.1
In other words, collect and factor. Of course, you should solve the actual problem by finding the angle that gives these tangents.
 one year ago

Dama28Best ResponseYou've already chosen the best response.0
now I need to find all real solutions with k being any integer.
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.1
You have \(\tan(\theta) = 0\), \(\tan(\theta) = \dfrac{1}{\sqrt{3}}\), and \(\tan(\theta) = \dfrac{1}{\sqrt{3}}\). Track them down.
 one year ago

Dama28Best ResponseYou've already chosen the best response.0
ok, so...for tan(θ)=0 I get 0 and pi. for tan(θ)=1/√3 I get pi/6 and 7pi/6. And for tan(θ)=−1/√3 I get 5pi/6 and 11pi/6. how do I know if I would add pi k to each or 2pi k?
 one year ago
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