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\(\large b^x = b^y \Rightarrow x = y \) iff \(\large b > 0, b \neq 1\)
Why b>0? Why not b ≠ 0?
 one year ago
 one year ago
\(\large b^x = b^y \Rightarrow x = y \) iff \(\large b > 0, b \neq 1\) Why b>0? Why not b ≠ 0?
 one year ago
 one year ago

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frecklesBest ResponseYou've already chosen the best response.2
(1)^3=(1)^5 => 3=5. True or false?
 one year ago

geerky42Best ResponseYou've already chosen the best response.0
Ok, how about b≠1, 0, 1? I just don't understand why b couldn't be smaller than zero...
 one year ago

frecklesBest ResponseYou've already chosen the best response.2
The statement did not work for b<0
 one year ago

geerky42Best ResponseYou've already chosen the best response.0
except 1... Why couldn't it be smaller than zero?
 one year ago

geerky42Best ResponseYou've already chosen the best response.0
Why not \(b \in \mathbb{R}, b \neq 1, 0, 1\)?
 one year ago

frecklesBest ResponseYou've already chosen the best response.2
Is the the thingy suppose to go both ways?
 one year ago

frecklesBest ResponseYou've already chosen the best response.2
Or do you mean it just in that one way?
 one year ago

geerky42Best ResponseYou've already chosen the best response.0
Well, both way, I guess.
 one year ago

geerky42Best ResponseYou've already chosen the best response.0
I found this statement in a iPhone app called Math Formulas, I think this is wrong, but I'm not sure...
 one year ago

frecklesBest ResponseYou've already chosen the best response.2
Well it is probably leading up to logarithms... Of course 1^n=1^m but this does not imply n=m.
 one year ago

frecklesBest ResponseYou've already chosen the best response.2
Oh you understand why b cannot be 1,0, or 1.
 one year ago

frecklesBest ResponseYou've already chosen the best response.2
Have you talked about logarithms?
 one year ago

frecklesBest ResponseYou've already chosen the best response.2
\[\log_b(x)=\frac{\ln(x)}{\ln(b)} , x>0, b>0, b \neq 1\]
 one year ago

frecklesBest ResponseYou've already chosen the best response.2
\[b^x=b^y\] \[\log_b(b^x)=\log_b(b^y)\] \[x \log_b(b)=y \log_b(b)\] \[x(1)=y(1)\] \[x=y\]
 one year ago

frecklesBest ResponseYou've already chosen the best response.2
That is assuming b>0 and b does not equal 1.
 one year ago

geerky42Best ResponseYou've already chosen the best response.0
Well, this makes sense. Thanks.
 one year ago
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