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geerky42
 3 years ago
\(\large b^x = b^y \Rightarrow x = y \) iff \(\large b > 0, b \neq 1\)
Why b>0? Why not b ≠ 0?
geerky42
 3 years ago
\(\large b^x = b^y \Rightarrow x = y \) iff \(\large b > 0, b \neq 1\) Why b>0? Why not b ≠ 0?

This Question is Closed

freckles
 3 years ago
Best ResponseYou've already chosen the best response.2(1)^3=(1)^5 => 3=5. True or false?

geerky42
 3 years ago
Best ResponseYou've already chosen the best response.0Ok, how about b≠1, 0, 1? I just don't understand why b couldn't be smaller than zero...

freckles
 3 years ago
Best ResponseYou've already chosen the best response.2The statement did not work for b<0

geerky42
 3 years ago
Best ResponseYou've already chosen the best response.0except 1... Why couldn't it be smaller than zero?

geerky42
 3 years ago
Best ResponseYou've already chosen the best response.0Why not \(b \in \mathbb{R}, b \neq 1, 0, 1\)?

freckles
 3 years ago
Best ResponseYou've already chosen the best response.2Is the the thingy suppose to go both ways?

freckles
 3 years ago
Best ResponseYou've already chosen the best response.2Or do you mean it just in that one way?

geerky42
 3 years ago
Best ResponseYou've already chosen the best response.0Well, both way, I guess.

geerky42
 3 years ago
Best ResponseYou've already chosen the best response.0I found this statement in a iPhone app called Math Formulas, I think this is wrong, but I'm not sure...

freckles
 3 years ago
Best ResponseYou've already chosen the best response.2Well it is probably leading up to logarithms... Of course 1^n=1^m but this does not imply n=m.

freckles
 3 years ago
Best ResponseYou've already chosen the best response.2Oh you understand why b cannot be 1,0, or 1.

freckles
 3 years ago
Best ResponseYou've already chosen the best response.2Have you talked about logarithms?

freckles
 3 years ago
Best ResponseYou've already chosen the best response.2\[\log_b(x)=\frac{\ln(x)}{\ln(b)} , x>0, b>0, b \neq 1\]

freckles
 3 years ago
Best ResponseYou've already chosen the best response.2\[b^x=b^y\] \[\log_b(b^x)=\log_b(b^y)\] \[x \log_b(b)=y \log_b(b)\] \[x(1)=y(1)\] \[x=y\]

freckles
 3 years ago
Best ResponseYou've already chosen the best response.2That is assuming b>0 and b does not equal 1.

geerky42
 3 years ago
Best ResponseYou've already chosen the best response.0Well, this makes sense. Thanks.
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