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jessica36j
Group Title
Got one more type I have read on and don't understand
2x  5y = 1
x 3y = 3
 one year ago
 one year ago
jessica36j Group Title
Got one more type I have read on and don't understand 2x  5y = 1 x 3y = 3
 one year ago
 one year ago

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BrianaNicole19 Group TitleBest ResponseYou've already chosen the best response.1
What are you trying to solve for?
 one year ago

jessica36j Group TitleBest ResponseYou've already chosen the best response.0
Find a solution to each system by the subsitution method.
 one year ago

BrianaNicole19 Group TitleBest ResponseYou've already chosen the best response.1
Try solving for y on the first equation and then replace what you found y to equal in the first equation into the second equation.. make sense?
 one year ago

jessica36j Group TitleBest ResponseYou've already chosen the best response.0
I think so I'll try it.... wish me luck
 one year ago

BrianaNicole19 Group TitleBest ResponseYou've already chosen the best response.1
Good luck(:
 one year ago

whatisthequestion Group TitleBest ResponseYou've already chosen the best response.1
I might be too late here but the far easier method is to solve for x in the second equation and sub that into the first equation
 one year ago

jessica36j Group TitleBest ResponseYou've already chosen the best response.0
oh ok thank you!!!! Ill try that way too
 one year ago

whatisthequestion Group TitleBest ResponseYou've already chosen the best response.1
yea anytime you are using substitution and you have an equation where one of the variables has a coefficient of 1 then use that equation to solve for that variable that way you will not run into fractions as much.
 one year ago

jessica36j Group TitleBest ResponseYou've already chosen the best response.0
Thank you!!! You have been so helpful!!!!
 one year ago
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