How much will $600 amount to be if it is invested at 10% interest compounded semiannually (two times a year) for 4 years?
A. $886.47
B. $952.40
C. $1063.20
D. $1168.17
\[A= P(1+\frac{r}{n})^{n\times t}\]A= amount you get
P = amount you invested
r = interest rate
n= no of time you get the interest
t = years of investment