Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
INT
Group Title
ïf each cation in fe3o4 has a coordination number of 4, What is the expected coordination number of each anion?
 one year ago
 one year ago
INT Group Title
ïf each cation in fe3o4 has a coordination number of 4, What is the expected coordination number of each anion?
 one year ago
 one year ago

This Question is Closed

Silent_Sorrow Group TitleBest ResponseYou've already chosen the best response.1
The overall coordination number should equal the charge of the molecule right? Since Fe3O4 has no charge it's overall coordination number will be zero. Iron will form the cation with coordination number +4, since there are 3 iron atoms present it's coordination will be +12, since there are 4 oxygen atoms present (oxygen forms the anion so negative number) 12/4=3
 one year ago

INT Group TitleBest ResponseYou've already chosen the best response.0
That seems to be the right answer. But does that mean that the coordination number is the same as the oxidation number?
 one year ago

Silent_Sorrow Group TitleBest ResponseYou've already chosen the best response.1
Sorry I got my ideas a bit muddled there. Fe3O4 is magnetite which is made up of both ferric oxide (Fe2O3, hematite) and ferrous oxide (FeO) I can't actually see how to find the anions coordination number for this molecule, the coordination number for transition metal compounds (for the cation) is just the number of ligands surrounding the central atom so I'm not too sure sorry
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.