## mayankdevnani 3 years ago A metal cube of edge 12 cm is melted and formed into three smaller cubes. If the edges of two smaller cubes are 6 cm and 8 cm . Find the edge of the third smaller cube.(Assume that there is no loss of metal during melting).

1. shamim

12*12*12=6*6*6+8*8*8+l*l*l

2. mayankdevnani

what???plz explain me

3. shamim

u hv to solve this equation

4. shamim

ok

5. shamim

the volume of larger cube is equal to the total volume of those small three cube

6. Outkast3r09

$V_{initial}=V_{final}$ \

7. shamim

ya u r righr

8. mayankdevnani

ok

9. shamim

do u wnt to get the solution of my equation

10. mayankdevnani

12*12*12=6*6*6+8*8*8+l*l*l |dw:1353831812338:dw|

11. shamim

no

12. mayankdevnani

req. eq 8*8*8+l*l*l=2*2*2

13. shamim

now i m going to explaining it

14. mayankdevnani

ok plz @shamim

15. shamim

now i m going to explaining it$12\times12\times12=6\times6\times6+8\times8\times8+l ^{3}$

16. shamim

$or, 1728=216+512+l ^{3}$

17. shamim

$or, l ^{3}=1728-216-512$

18. shamim

$or, l ^{3}=1000$

19. mayankdevnani

$l^3=1000$ $l=10cm$

20. shamim

$or, l=10$

21. mayankdevnani

right @shamim

22. shamim

ya u r right

23. mayankdevnani

thnxx....

24. shamim

welcome