mayankdevnani
A metal cube of edge 12 cm is melted and formed into three smaller cubes. If the edges of two smaller cubes are 6 cm and 8 cm . Find the edge of the third smaller cube.(Assume that there is no loss of metal during melting).
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shamim
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12*12*12=6*6*6+8*8*8+l*l*l
mayankdevnani
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what???plz explain me
shamim
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u hv to solve this equation
shamim
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ok
shamim
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the volume of larger cube is equal to the total volume of those small three cube
Outkast3r09
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\[V_{initial}=V_{final}\]
\
shamim
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ya u r righr
mayankdevnani
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ok
shamim
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do u wnt to get the solution of my equation
mayankdevnani
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12*12*12=6*6*6+8*8*8+l*l*l
|dw:1353831812338:dw|
shamim
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no
mayankdevnani
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req. eq
8*8*8+l*l*l=2*2*2
shamim
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now i m going to explaining it
mayankdevnani
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ok plz @shamim
shamim
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now i m going to explaining it\[12\times12\times12=6\times6\times6+8\times8\times8+l ^{3}\]
shamim
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\[or, 1728=216+512+l ^{3}\]
shamim
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\[or, l ^{3}=1728-216-512\]
shamim
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\[or, l ^{3}=1000\]
mayankdevnani
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\[l^3=1000\]
\[l=10cm\]
shamim
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\[or, l=10\]
mayankdevnani
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right @shamim
shamim
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ya u r right
mayankdevnani
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thnxx....
shamim
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welcome