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Solve 0.7x = 22. Round your answer to the nearest hundredth. A. x ≈ -7.12 B. x ≈ 8.45 C. x ≈ -8.67 D. x ≈ 9.34

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\[0.7x=22\]divide both sides by \(0.7\) to isolate x:\[{\cancel{0.7}{x}\over\cancel{0.7}}={22\over0.7}\]\[x={22\over0.7}\]\[x=31.428571...\]\[x\approx31.43\]i think your options are incorrect, check to make sure
i dont have any other options, other than these 4
well then the options are incorrect because what i worked out is accurate...maybe its a misprint?

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i dont think so....this is how long it took to solve this one : x=log35 log35=log105log103≈0.698970.47712≈1.46
31.42is ans
i think u wrote down the question incorrectly. it should be \[0.7^{x}=22\] then using the base change formula it should be \[x= \frac{ \log22 }{ \log0.7 } \approx -8.67\]

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