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dasDaName
Group Title
Solve 0.7x = 22. Round your answer to the nearest hundredth.
A. x ≈ 7.12
B. x ≈ 8.45
C. x ≈ 8.67
D. x ≈ 9.34
 one year ago
 one year ago
dasDaName Group Title
Solve 0.7x = 22. Round your answer to the nearest hundredth. A. x ≈ 7.12 B. x ≈ 8.45 C. x ≈ 8.67 D. x ≈ 9.34
 one year ago
 one year ago

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yummydum Group TitleBest ResponseYou've already chosen the best response.0
\[0.7x=22\]divide both sides by \(0.7\) to isolate x:\[{\cancel{0.7}{x}\over\cancel{0.7}}={22\over0.7}\]\[x={22\over0.7}\]\[x=31.428571...\]\[x\approx31.43\]i think your options are incorrect, check to make sure
 one year ago

dasDaName Group TitleBest ResponseYou've already chosen the best response.0
i dont have any other options, other than these 4
 one year ago

yummydum Group TitleBest ResponseYou've already chosen the best response.0
well then the options are incorrect because what i worked out is accurate...maybe its a misprint?
 one year ago

dasDaName Group TitleBest ResponseYou've already chosen the best response.0
i dont think so....this is how long it took to solve this one : x=log35 log35=log105log103≈0.698970.47712≈1.46
 one year ago

yummydum Group TitleBest ResponseYou've already chosen the best response.0
@UnkleRhaukus help?
 one year ago

sunnymony Group TitleBest ResponseYou've already chosen the best response.0
31.42is ans
 one year ago

technofable Group TitleBest ResponseYou've already chosen the best response.1
i think u wrote down the question incorrectly. it should be \[0.7^{x}=22\] then using the base change formula it should be \[x= \frac{ \log22 }{ \log0.7 } \approx 8.67\]
 one year ago
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