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sunnymony Group TitleBest ResponseYou've already chosen the best response.1
e^tdy/dt=y^3 dyv^3=dt e^t on integratiion y^2/2=e^t/1 +constant
 one year ago

mays Group TitleBest ResponseYou've already chosen the best response.0
than you very much
 one year ago

sunnymony Group TitleBest ResponseYou've already chosen the best response.1
ur welcome
 one year ago

mays Group TitleBest ResponseYou've already chosen the best response.0
if i need the general solution of the differential equation expressing y explicitly as a function of t and hence find the particular solution that satisfies the initial y(0)=1 do i need to make it y=f(x) then find the constant c then substitute the value of x through f(x) thanks
 one year ago

scarydoor Group TitleBest ResponseYou've already chosen the best response.0
Have you written the question correctly? A first order nonlinear differential equation? (nonlinear?) Wolfram gives: http://www.wolframalpha.com/input/?i=e^t+dy%2Fdt%3Dy^3 A wacky solution... it seems to be interpreting it correctly, as least how I would think of it from what you've written...
 one year ago

mays Group TitleBest ResponseYou've already chosen the best response.0
yes its true e^t *dy/dt=y^3 (where y is gretethan 0) but i use the wolframalpha but itesnt go right whatdo you thinease
 one year ago

mays Group TitleBest ResponseYou've already chosen the best response.0
sorry what do you think please
 one year ago

scarydoor Group TitleBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/ Type into the search the problem: e^t *dy/dt=y^3 It will solve it. But it's not a nice looking solution...
 one year ago

mays Group TitleBest ResponseYou've already chosen the best response.0
the answer i got is y=1/2e^t+2c
 one year ago

mays Group TitleBest ResponseYou've already chosen the best response.0
and this without computr
 one year ago

scarydoor Group TitleBest ResponseYou've already chosen the best response.0
actually the solution the other guy gave is right. But it's written implicitly not explicity, which is why it looks different to what wolfram gives. But still the solution is very ugly. If this is for a class assignment then I think this is either written incorrectly, or it's supposed to look ugly for some reason (maybe it's from a real life problem).
 one year ago

mays Group TitleBest ResponseYou've already chosen the best response.0
ok thanks lot will try it again
 one year ago

scarydoor Group TitleBest ResponseYou've already chosen the best response.0
here's the solution that the other guy gave: 1/2 * y^(2) = e^(t) + C. I think that's right. But see how that's written in implicit form. If you solve that for y then I think you should end up with what wolfram alpha got.
 one year ago
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