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sunnymony
 2 years ago
Best ResponseYou've already chosen the best response.1e^tdy/dt=y^3 dyv^3=dt e^t on integratiion y^2/2=e^t/1 +constant

mays
 2 years ago
Best ResponseYou've already chosen the best response.0if i need the general solution of the differential equation expressing y explicitly as a function of t and hence find the particular solution that satisfies the initial y(0)=1 do i need to make it y=f(x) then find the constant c then substitute the value of x through f(x) thanks

scarydoor
 2 years ago
Best ResponseYou've already chosen the best response.0Have you written the question correctly? A first order nonlinear differential equation? (nonlinear?) Wolfram gives: http://www.wolframalpha.com/input/?i=e^t+dy%2Fdt%3Dy^3 A wacky solution... it seems to be interpreting it correctly, as least how I would think of it from what you've written...

mays
 2 years ago
Best ResponseYou've already chosen the best response.0yes its true e^t *dy/dt=y^3 (where y is gretethan 0) but i use the wolframalpha but itesnt go right whatdo you thinease

mays
 2 years ago
Best ResponseYou've already chosen the best response.0sorry what do you think please

scarydoor
 2 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/ Type into the search the problem: e^t *dy/dt=y^3 It will solve it. But it's not a nice looking solution...

mays
 2 years ago
Best ResponseYou've already chosen the best response.0the answer i got is y=1/2e^t+2c

scarydoor
 2 years ago
Best ResponseYou've already chosen the best response.0actually the solution the other guy gave is right. But it's written implicitly not explicity, which is why it looks different to what wolfram gives. But still the solution is very ugly. If this is for a class assignment then I think this is either written incorrectly, or it's supposed to look ugly for some reason (maybe it's from a real life problem).

mays
 2 years ago
Best ResponseYou've already chosen the best response.0ok thanks lot will try it again

scarydoor
 2 years ago
Best ResponseYou've already chosen the best response.0here's the solution that the other guy gave: 1/2 * y^(2) = e^(t) + C. I think that's right. But see how that's written in implicit form. If you solve that for y then I think you should end up with what wolfram alpha got.
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