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find dy/dy of y + sinxy = x

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question is wrong
sorry it is Find dy/dx by implicit differentiation.
ya thats true

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Other answers:

dy/dx is still wrong?
on differention dy wrt to dy
Differentiate both sides, dy/dx+cos(xy) dy/dx=1 =>dy/dx(1+cos xy)=1 => dy/dx=1/(1+cos(xy))
Remember to differentiate the (xy) term in sin(xy) to get correct answer!
Question is find dy/dx of y+sinxy=x
ok 1+cos(xy) x=0 cosxy=-1/x
ok thanks all

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