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Find all distinct roots(real or complex) of
z^2 + (9+3i)z + (24+11i) in the form a+bi.
Hint: You may have to complete the square
 one year ago
 one year ago
Find all distinct roots(real or complex) of z^2 + (9+3i)z + (24+11i) in the form a+bi. Hint: You may have to complete the square
 one year ago
 one year ago

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iop360Best ResponseYou've already chosen the best response.0
http://answers.yahoo.com/question/index?qid=20121124223053AAchfPc the bottom explanation of this link might be it, but i dont understand it
 one year ago

iop360Best ResponseYou've already chosen the best response.0
have you figured anything out?
 one year ago

sirm3dBest ResponseYou've already chosen the best response.0
\[\large z^2+(9+3i)z+(2411i)=0\]\[\large z^2+(9+3i)z=(2411i)\]to complete squares, add (b/2)^2 to both sides, where b=9+3i \[\large z^2+(9+3i)z+\left( \frac{ 9+3i }{ 2 } \right)^2=(2411i)+\left( \frac{ 9+3i }{ 2 } \right)^2\]
 one year ago

iop360Best ResponseYou've already chosen the best response.0
yeah im at this step... what do you do next?
 one year ago

iop360Best ResponseYou've already chosen the best response.0
\[(z + (\frac{ 9 + 3i }{ 2 }))^2 = 24 + 11i + 18 +\frac{ 27i }{ 2 }\]
 one year ago

iop360Best ResponseYou've already chosen the best response.0
\[z + (\frac{ 9+3i }{ 2 }) = \pm \sqrt{\frac{ 12 + 5i}{ 2 }} \]
 one year ago

iop360Best ResponseYou've already chosen the best response.0
i dont get how the person completed the square in the yahoo link..
 one year ago

iop360Best ResponseYou've already chosen the best response.0
\[z = (\frac{ 9+3i }{ 2}) \pm \sqrt{\frac{ 12 + 5i }{ 2 }}\]
 one year ago

iop360Best ResponseYou've already chosen the best response.0
it would be so much easier if the square root wasnt there...we could just add them up easily
 one year ago

iop360Best ResponseYou've already chosen the best response.0
from the yahoo answers link: z² + (2−4i)z = (11+10i) z² + (2−4i)z + (3 4i) = (11+10i) + (3 4i)
 one year ago

iop360Best ResponseYou've already chosen the best response.0
what i dont get is where the (34i) comes from
 one year ago
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