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have you figured anything out?

yeah im at this step... what do you do next?

\[(z + (\frac{ 9 + 3i }{ 2 }))^2 = -24 + 11i + 18 +\frac{ 27i }{ 2 }\]

\[z + (\frac{ 9+3i }{ 2 }) = \pm \sqrt{\frac{ -12 + 5i}{ 2 }} \]

i dunno, lol

i dont get how the person completed the square in the yahoo link..

\[z = -(\frac{ 9+3i }{ 2}) \pm \sqrt{\frac{ -12 + 5i }{ 2 }}\]

it would be so much easier if the square root wasnt there...we could just add them up easily

from the yahoo answers link:
z² + (2−4i)z = (11+10i)
z² + (2−4i)z + (-3 -4i) = (11+10i) + (-3 -4i)

what i dont get is where the (-3-4i) comes from