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babydoll332

  • 3 years ago

Find all solutions in the interval [0, 2π). sin^2x + sin x = 0

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  1. cwrw238
    • 3 years ago
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    factoring sinx ( sinx + 1) = 0 sinx = 0 or -1

  2. babydoll332
    • 3 years ago
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    wouldnt it be pi/3 and pi

  3. artix_17
    • 3 years ago
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    x=0

  4. babydoll332
    • 3 years ago
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    yes i know o, pi but im not sure if the further one is pi/3

  5. artix_17
    • 3 years ago
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    how did you get pi/3

  6. babydoll332
    • 3 years ago
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    i useed the identities

  7. cwrw238
    • 3 years ago
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    for sin x = -1 x = 270 degrees or 3pi/2

  8. babydoll332
    • 3 years ago
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    just kidding i got 3pi/2

  9. artix_17
    • 3 years ago
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    LOL

  10. cwrw238
    • 3 years ago
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    lol

  11. babydoll332
    • 3 years ago
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    i saw it right when i was typing thnks guys ":)

  12. cwrw238
    • 3 years ago
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    sin x = 0 for angle x = pi as well

  13. babydoll332
    • 3 years ago
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    yes i know thanks <3

  14. babydoll332
    • 3 years ago
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    and o ofcourse

  15. cwrw238
    • 3 years ago
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    so 3 solution x = 0, pi and 3pi/2

  16. babydoll332
    • 3 years ago
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    yes thanks :)

  17. cwrw238
    • 3 years ago
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    yw

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