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ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1353856476119:dw
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
What do you have to do?
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
i am gettingy=1x+1 but the answer is 1x+1 nothing but the slope
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
find derivative of y to find teh slope
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
and then equation of line
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
\[\huge \frac {d\frac{1}{1+\frac{sinx}{cosx}}} {dx}= \frac {d\frac{1}{1+\frac{sinx}{cosx}}} {d\frac{sinx}{cosx}} \frac {d\frac{sinx}{cosx}} {dx}\]
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
\[\huge = \frac{1}{(1+\frac{sinx}{cosx})^2} \frac{1}{cos^2x}\]
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
i know tanx=sec^2x
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
which is 1/cos^2x
 2 years ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
\[\left(\begin{matrix}\sec^2(0) \\ 1+\tan^2(0)\end{matrix}\right)\]
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
\[\huge \text{ when } a=0 , \text{ it is }\] \[\huge \frac{1}{(1\frac{0}{1})^2}\frac{1}{1^2}=1\]
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
\[\huge y=x+k\] What is k? When x=0, \[\huge y=\frac{1}{1+0}=1\] Inserting \[ \huge (0,1) \] into \[\huge y=x+k\], we have \[\huge 1=0+k\] \[ \huge \Rightarrow k=1 \] \[\huge \Rightarrow y=x+1\]
 2 years ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
Shout if confused
 2 years ago
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