Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

ksaimouli

  • 2 years ago

linearization

  • This Question is Closed
  1. ksaimouli
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1353856476119:dw|

  2. ksaimouli
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    a=0

  3. henpen
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    What do you have to do?

  4. ksaimouli
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i am gettingy=1x+1 but the answer is -1x+1 nothing but the slope

  5. ksaimouli
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    find derivative of y to find teh slope

  6. ksaimouli
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and then equation of line

  7. henpen
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\huge \frac {d\frac{1}{1+\frac{sinx}{cosx}}} {dx}= \frac {d\frac{1}{1+\frac{sinx}{cosx}}} {d\frac{sinx}{cosx}} \frac {d\frac{sinx}{cosx}} {dx}\]

  8. henpen
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\huge = \frac{-1}{(1+\frac{sinx}{cosx})^2} \frac{1}{cos^2x}\]

  9. ksaimouli
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i know tanx=sec^2x

  10. ksaimouli
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    which is 1/cos^2x

  11. ksaimouli
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\left(\begin{matrix}-\sec^2(0) \\ 1+\tan^2(0)\end{matrix}\right)\]

  12. ksaimouli
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    =1???

  13. henpen
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\huge \text{ when } a=0 , \text{ it is }\] \[\huge \frac{-1}{(1-\frac{0}{1})^2}\frac{1}{1^2}=-1\]

  14. henpen
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\huge y=-x+k\] What is k? When x=0, \[\huge y=\frac{1}{1+0}=1\] Inserting \[ \huge (0,1) \] into \[\huge y=-x+k\], we have \[\huge 1=-0+k\] \[ \huge \Rightarrow k=1 \] \[\huge \Rightarrow y=-x+1\]

  15. henpen
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Shout if confused

  16. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.