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ksaimouli
 3 years ago
linearization
ksaimouli
 3 years ago
linearization

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ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1353856476119:dw

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0i am gettingy=1x+1 but the answer is 1x+1 nothing but the slope

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0find derivative of y to find teh slope

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0and then equation of line

henpen
 3 years ago
Best ResponseYou've already chosen the best response.1\[\huge \frac {d\frac{1}{1+\frac{sinx}{cosx}}} {dx}= \frac {d\frac{1}{1+\frac{sinx}{cosx}}} {d\frac{sinx}{cosx}} \frac {d\frac{sinx}{cosx}} {dx}\]

henpen
 3 years ago
Best ResponseYou've already chosen the best response.1\[\huge = \frac{1}{(1+\frac{sinx}{cosx})^2} \frac{1}{cos^2x}\]

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0\[\left(\begin{matrix}\sec^2(0) \\ 1+\tan^2(0)\end{matrix}\right)\]

henpen
 3 years ago
Best ResponseYou've already chosen the best response.1\[\huge \text{ when } a=0 , \text{ it is }\] \[\huge \frac{1}{(1\frac{0}{1})^2}\frac{1}{1^2}=1\]

henpen
 3 years ago
Best ResponseYou've already chosen the best response.1\[\huge y=x+k\] What is k? When x=0, \[\huge y=\frac{1}{1+0}=1\] Inserting \[ \huge (0,1) \] into \[\huge y=x+k\], we have \[\huge 1=0+k\] \[ \huge \Rightarrow k=1 \] \[\huge \Rightarrow y=x+1\]
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