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ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1353856476119:dw
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
What do you have to do?
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
i am gettingy=1x+1 but the answer is 1x+1 nothing but the slope
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
find derivative of y to find teh slope
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
and then equation of line
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
\[\huge \frac {d\frac{1}{1+\frac{sinx}{cosx}}} {dx}= \frac {d\frac{1}{1+\frac{sinx}{cosx}}} {d\frac{sinx}{cosx}} \frac {d\frac{sinx}{cosx}} {dx}\]
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
\[\huge = \frac{1}{(1+\frac{sinx}{cosx})^2} \frac{1}{cos^2x}\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
i know tanx=sec^2x
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
which is 1/cos^2x
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
\[\left(\begin{matrix}\sec^2(0) \\ 1+\tan^2(0)\end{matrix}\right)\]
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
\[\huge \text{ when } a=0 , \text{ it is }\] \[\huge \frac{1}{(1\frac{0}{1})^2}\frac{1}{1^2}=1\]
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
\[\huge y=x+k\] What is k? When x=0, \[\huge y=\frac{1}{1+0}=1\] Inserting \[ \huge (0,1) \] into \[\huge y=x+k\], we have \[\huge 1=0+k\] \[ \huge \Rightarrow k=1 \] \[\huge \Rightarrow y=x+1\]
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.1
Shout if confused
 one year ago
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