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ksaimouli

  • 2 years ago

a woman 5 feet tall is walking away from a streetlight hung 20 feet from the ground at a rate of 6ft how fast the shadow lengthing

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  1. ksaimouli
    • 2 years ago
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    |dw:1353865196344:dw|

  2. ksaimouli
    • 2 years ago
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    beside 5 is 20

  3. ksaimouli
    • 2 years ago
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    i just want

  4. ksaimouli
    • 2 years ago
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    similar triangle

  5. ksaimouli
    • 2 years ago
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    can i use |dw:1353865365236:dw|

  6. ksaimouli
    • 2 years ago
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    @hartnn

  7. asnaseer
    • 2 years ago
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    you are using exactly the right approach. find x in terms of y and then differentiate with respect to time to get your answer.

  8. ksaimouli
    • 2 years ago
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    i know i got 18 but book used another one |dw:1353865556968:dw|

  9. ksaimouli
    • 2 years ago
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    which is right way

  10. ksaimouli
    • 2 years ago
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    they got 2ft/sec

  11. asnaseer
    • 2 years ago
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    I think you have an error in your calculation. If I use the same ratio as you showed initially then I get an answer of 2 ft/s

  12. ksaimouli
    • 2 years ago
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    hmmm

  13. asnaseer
    • 2 years ago
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    maybe if you listed your steps then I may be able to help you spot where you may have made a mistake

  14. ksaimouli
    • 2 years ago
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    |dw:1353865761171:dw|

  15. ksaimouli
    • 2 years ago
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    |dw:1353865816040:dw|

  16. ksaimouli
    • 2 years ago
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    dx/dt=6

  17. asnaseer
    • 2 years ago
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    sorry I meant that you have been given dy/dt = 6

  18. asnaseer
    • 2 years ago
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    x represents the shadow length

  19. ksaimouli
    • 2 years ago
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    so the shadow falls in front of her because the light is backwards?

  20. asnaseer
    • 2 years ago
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    yes - but I would say the light is behind her rather than "backwards" :)

  21. ksaimouli
    • 2 years ago
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    thx becasue of silly mistake whole answer is wrong thx for correcting me

  22. asnaseer
    • 2 years ago
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    yw :)

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