a woman 5 feet tall is walking away from a streetlight hung 20 feet from the ground at a rate of 6ft how fast the shadow lengthing

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a woman 5 feet tall is walking away from a streetlight hung 20 feet from the ground at a rate of 6ft how fast the shadow lengthing

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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|dw:1353865196344:dw|
beside 5 is 20
i just want

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Other answers:

similar triangle
can i use |dw:1353865365236:dw|
you are using exactly the right approach. find x in terms of y and then differentiate with respect to time to get your answer.
i know i got 18 but book used another one |dw:1353865556968:dw|
which is right way
they got 2ft/sec
I think you have an error in your calculation. If I use the same ratio as you showed initially then I get an answer of 2 ft/s
hmmm
maybe if you listed your steps then I may be able to help you spot where you may have made a mistake
|dw:1353865761171:dw|
|dw:1353865816040:dw|
dx/dt=6
sorry I meant that you have been given dy/dt = 6
x represents the shadow length
so the shadow falls in front of her because the light is backwards?
yes - but I would say the light is behind her rather than "backwards" :)
thx becasue of silly mistake whole answer is wrong thx for correcting me
yw :)

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