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\[g(f(x))=g(2x-1)=\sqrt{2x-1}\]

@satellite73 why is g(2x-1) sqrt(2x-1) instead of 2*sqrt(x)-1?

@livelaughlilz You have to substitute the value of
\[f(x)=2x-1\]
In place of
x
in
\[g(x)=\sqrt(x)\]