anonymous
  • anonymous
Find the centroid of the area:
Mathematics
katieb
  • katieb
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
|dw:1353879322184:dw|
anonymous
  • anonymous
I got 5/9 as my answer which isn't right...

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anonymous
  • anonymous
Yeah, 5/9 is way too big. Do you only need x-bar and not y-bar?
anonymous
  • anonymous
Only x bar.
anonymous
  • anonymous
So apparently the correct answer is 0.278 but I dont see how...
anonymous
  • anonymous
Is this what you started with? \[\huge x-bar=\frac{\int x^{5/4} dx}{\int x^{1/4} dx} \]
anonymous
  • anonymous
Yep.
anonymous
  • anonymous
The limits of integration are from 0 to 1 I believe.
anonymous
  • anonymous
Hmm, seems to be something missing..
anonymous
  • anonymous
Well the curve on the top is technically y=1.
anonymous
  • anonymous
I think you need to switch x and y to find x-bar and y-bar. i.e. for x-bar it is integral of y dA, and for y-bar it is integral of x dA.
anonymous
  • anonymous
See here for more info: http://tutorial.math.lamar.edu/Classes/CalcII/CenterOfMass.aspx

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