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3kgtlife Group Title

Solve the logarithmic equation. log 4 x=log 3 + log(x+3)

  • 2 years ago
  • 2 years ago

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  1. asnaseer Group Title
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    use this log rule to first simplify the right-hand-side:\[\log(a)+\log(b)=\log(ab)\]

    • 2 years ago
  2. 3kgtlife Group Title
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    log(3)+log(4x)=log(x+3)??

    • 2 years ago
  3. asnaseer Group Title
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    where did you get that from?

    • 2 years ago
  4. asnaseer Group Title
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    use the rule I gave to first simplify this:\[\log 3 + \log(x+3)\]

    • 2 years ago
  5. ksaimouli Group Title
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    |dw:1353881624386:dw|

    • 2 years ago
  6. 3kgtlife Group Title
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    okk

    • 2 years ago
  7. ksaimouli Group Title
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    use as she says

    • 2 years ago
  8. ksaimouli Group Title
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    log 4x/3

    • 2 years ago
  9. 3kgtlife Group Title
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    what do I do after that?

    • 2 years ago
  10. ksaimouli Group Title
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    http://www.sosmath.com/algebra/logs/log4/log44/log44.html

    • 2 years ago
  11. ksaimouli Group Title
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    first learn rules

    • 2 years ago
  12. asnaseer Group Title
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    what do you get after using the rule for this expression?\[\log 3 + \log(x+3)\]

    • 2 years ago
  13. asnaseer Group Title
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    @3kgtlife do you understand?

    • 2 years ago
  14. 3kgtlife Group Title
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    Im trying hold up

    • 2 years ago
  15. 3kgtlife Group Title
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    I am lost

    • 2 years ago
  16. asnaseer Group Title
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    do you know the various rules for logs?

    • 2 years ago
  17. 3kgtlife Group Title
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    no

    • 2 years ago
  18. asnaseer Group Title
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    Then I suggest you first learn about them (using the link posted by ksaimouli above) and then come back to do this problem.

    • 2 years ago
  19. 3kgtlife Group Title
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    alright thanks

    • 2 years ago
  20. asnaseer Group Title
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    yw :)

    • 2 years ago
  21. Luiz Group Title
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    use log rules: log(a) + log(b) = log(a*b) 10^log(a)=a

    • 2 years ago
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