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3kgtlife

  • 3 years ago

Solve the logarithmic equation. log 4 x=log 3 + log(x+3)

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  1. asnaseer
    • 3 years ago
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    use this log rule to first simplify the right-hand-side:\[\log(a)+\log(b)=\log(ab)\]

  2. 3kgtlife
    • 3 years ago
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    log(3)+log(4x)=log(x+3)??

  3. asnaseer
    • 3 years ago
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    where did you get that from?

  4. asnaseer
    • 3 years ago
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    use the rule I gave to first simplify this:\[\log 3 + \log(x+3)\]

  5. ksaimouli
    • 3 years ago
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    |dw:1353881624386:dw|

  6. 3kgtlife
    • 3 years ago
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    okk

  7. ksaimouli
    • 3 years ago
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    use as she says

  8. ksaimouli
    • 3 years ago
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    log 4x/3

  9. 3kgtlife
    • 3 years ago
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    what do I do after that?

  10. ksaimouli
    • 3 years ago
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    http://www.sosmath.com/algebra/logs/log4/log44/log44.html

  11. ksaimouli
    • 3 years ago
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    first learn rules

  12. asnaseer
    • 3 years ago
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    what do you get after using the rule for this expression?\[\log 3 + \log(x+3)\]

  13. asnaseer
    • 3 years ago
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    @3kgtlife do you understand?

  14. 3kgtlife
    • 3 years ago
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    Im trying hold up

  15. 3kgtlife
    • 3 years ago
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    I am lost

  16. asnaseer
    • 3 years ago
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    do you know the various rules for logs?

  17. 3kgtlife
    • 3 years ago
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    no

  18. asnaseer
    • 3 years ago
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    Then I suggest you first learn about them (using the link posted by ksaimouli above) and then come back to do this problem.

  19. 3kgtlife
    • 3 years ago
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    alright thanks

  20. asnaseer
    • 3 years ago
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    yw :)

  21. Luiz
    • 3 years ago
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    use log rules: log(a) + log(b) = log(a*b) 10^log(a)=a

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