A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Solve the logarithmic equation.
log 4 x=log 3 + log(x+3)
anonymous
 3 years ago
Solve the logarithmic equation. log 4 x=log 3 + log(x+3)

This Question is Open

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.0use this log rule to first simplify the righthandside:\[\log(a)+\log(b)=\log(ab)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0log(3)+log(4x)=log(x+3)??

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.0where did you get that from?

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.0use the rule I gave to first simplify this:\[\log 3 + \log(x+3)\]

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1353881624386:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what do I do after that?

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.0what do you get after using the rule for this expression?\[\log 3 + \log(x+3)\]

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.0@3kgtlife do you understand?

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.0do you know the various rules for logs?

asnaseer
 3 years ago
Best ResponseYou've already chosen the best response.0Then I suggest you first learn about them (using the link posted by ksaimouli above) and then come back to do this problem.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0use log rules: log(a) + log(b) = log(a*b) 10^log(a)=a
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.