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refusetofail
 3 years ago
find & simplify the difference quotient
[f(x+h)f(x)]/ h, where h cannot = 0
for the given funtion: f(x)=2x^2+4x+3
refusetofail
 3 years ago
find & simplify the difference quotient [f(x+h)f(x)]/ h, where h cannot = 0 for the given funtion: f(x)=2x^2+4x+3

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cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.1this is 2(x+h)^2+4(x+h) +3  (2x^2+4x+3)  h

refusetofail
 3 years ago
Best ResponseYou've already chosen the best response.0yes, I realise that.. but after I group and simplify, I end up with h=2 but that's not the answer in my textbook, I'm not sure where I went wrong:/

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.1i don't quite understand what u want here  this function produces the derivative of the f(x) when h > 0 i.e. limit of it as h> 0 . its not about finding a value of h

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1353883607543:dw

refusetofail
 3 years ago
Best ResponseYou've already chosen the best response.0well the answer is apparently, 2x +h + 6 and I don't understand how to get this

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.1the answer should be 4x + 4 + h

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.12(x+h)^2+4(x+h) +3  (2x^2+4x+3) = 2x^2 + 4xh + 2h^2 + 4x + 4h + 3  2x^2  4x  3 = 4xh + + 4h + 2h^2 dividing this by h gives 4x + 4 + 2h  i was wrong in my last post

refusetofail
 3 years ago
Best ResponseYou've already chosen the best response.0but that's still not the answer I was given.. is it wrong then?

refusetofail
 3 years ago
Best ResponseYou've already chosen the best response.0turns out the ansser given is wrong, thanks :)
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