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refusetofail

  • 3 years ago

find & simplify the difference quotient [f(x+h)-f(x)]/ h, where h cannot = 0 for the given funtion: f(x)=2x^2+4x+3

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  1. cwrw238
    • 3 years ago
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    this is 2(x+h)^2+4(x+h) +3 - (2x^2+4x+3) -------------------------------- h

  2. refusetofail
    • 3 years ago
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    yes, I realise that.. but after I group and simplify, I end up with h=-2 but that's not the answer in my textbook, I'm not sure where I went wrong:/

  3. cwrw238
    • 3 years ago
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    i don't quite understand what u want here - this function produces the derivative of the f(x) when h --> 0 i.e. limit of it as h---> 0 . its not about finding a value of h

  4. ksaimouli
    • 3 years ago
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    |dw:1353883607543:dw|

  5. refusetofail
    • 3 years ago
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    well the answer is apparently, 2x +h + 6 and I don't understand how to get this

  6. cwrw238
    • 3 years ago
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    the answer should be 4x + 4 + h

  7. cwrw238
    • 3 years ago
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    2(x+h)^2+4(x+h) +3 - (2x^2+4x+3) = 2x^2 + 4xh + 2h^2 + 4x + 4h + 3 - 2x^2 - 4x - 3 = 4xh + + 4h + 2h^2 dividing this by h gives 4x + 4 + 2h - i was wrong in my last post

  8. refusetofail
    • 3 years ago
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    but that's still not the answer I was given.. is it wrong then?

  9. refusetofail
    • 3 years ago
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    turns out the ansser given is wrong, thanks :)

  10. refusetofail
    • 3 years ago
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    **answer

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