CALCULUS HELP
(1 pt) Consider the function f(x) = 2 x^3 - 5 x on the interval [ -2 , 2 ]. Find the average or mean slope of the function on this interval. By the Mean Value Theorem, we know there exists at least one c in the open interval ( -2 , 2 ) such that f'( c) is equal to this mean slope. For this problem, there are two values of c that work. The smaller one is= and the larger one is= i found the mean slope=3 but cannot get the values where f'(c) is equal to 3.... tried setting the derivative equal to three but that doesnt yield the right answer, or im not working it out right....please

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u mena find the equation of tangent line?

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