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gnarballs

  • 2 years ago

CALCULUS HELP (1 pt) Consider the function f(x) = 2 x^3 - 5 x on the interval [ -2 , 2 ]. Find the average or mean slope of the function on this interval. By the Mean Value Theorem, we know there exists at least one c in the open interval ( -2 , 2 ) such that f'( c) is equal to this mean slope. For this problem, there are two values of c that work. The smaller one is= and the larger one is= i found the mean slope=3 but cannot get the values where f'(c) is equal to 3.... tried setting the derivative equal to three but that doesnt yield the right answer, or im not working it out right....please

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  1. ksaimouli
    • 2 years ago
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    u mena find the equation of tangent line?

  2. ksaimouli
    • 2 years ago
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    |dw:1353882845431:dw|

  3. gnarballs
    • 2 years ago
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    i dont think so... i need to find where f' is = to the mean slope(3) on the interval (-2,2)..tried setting f' =3 but with no luck

  4. ksaimouli
    • 2 years ago
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    ok it means the same ok so use the formula above

  5. ksaimouli
    • 2 years ago
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    find derivative first

  6. ksaimouli
    • 2 years ago
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    what did u get

  7. gnarballs
    • 2 years ago
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    6x^2-5

  8. ksaimouli
    • 2 years ago
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    now calculate |dw:1353883173646:dw|

  9. gnarballs
    • 2 years ago
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    its 3

  10. ksaimouli
    • 2 years ago
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    set the derivative=3 solve for x

  11. gnarballs
    • 2 years ago
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    awesome, found my mistake...thank you man

  12. ksaimouli
    • 2 years ago
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    what did u get?

  13. gnarballs
    • 2 years ago
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    -1.1545, 1.1545

  14. ksaimouli
    • 2 years ago
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    yup u got it yup

  15. ksaimouli
    • 2 years ago
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    anymore question>

  16. gnarballs
    • 2 years ago
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    yes .. (1 pt) Consider the function f(x) = 1/x on the interval [ 1 , 10 ]. (A) Find the average or mean slope of the function on this interval. - i found it to be -.1 (B) By the Mean Value Theorem, we know there exists a c in the open interval ( 1 , 10 ) such that f'( c) is equal to this mean slope. Find all values of c that work and list them (separated by commas) in the box below. - i set -1/x^2 = -.1 and got -3.1622 and 3.1622 but it doesnt accept those as answers

  17. ksaimouli
    • 2 years ago
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    yup

  18. ksaimouli
    • 2 years ago
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    correct

  19. gnarballs
    • 2 years ago
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    ok i had to use only the positive one since it was in the interval given........thank you for your help..... have an awesome day !

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