u mena find the equation of tangent line?
i dont think so... i need to find where f' is = to the mean slope(3) on the interval (-2,2)..tried setting f' =3 but with no luck
ok it means the same ok so use the formula above
find derivative first
what did u get
now calculate |dw:1353883173646:dw|
set the derivative=3 solve for x
awesome, found my mistake...thank you man
what did u get?
yup u got it yup
yes .. (1 pt) Consider the function f(x) = 1/x on the interval [ 1 , 10 ]. (A) Find the average or mean slope of the function on this interval. - i found it to be -.1 (B) By the Mean Value Theorem, we know there exists a c in the open interval ( 1 , 10 ) such that f'( c) is equal to this mean slope. Find all values of c that work and list them (separated by commas) in the box below. - i set -1/x^2 = -.1 and got -3.1622 and 3.1622 but it doesnt accept those as answers
ok i had to use only the positive one since it was in the interval given........thank you for your help..... have an awesome day !