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gnarballs

CALCULUS HELP (1 pt) Consider the function f(x) = 2 x^3 - 5 x on the interval [ -2 , 2 ]. Find the average or mean slope of the function on this interval. By the Mean Value Theorem, we know there exists at least one c in the open interval ( -2 , 2 ) such that f'( c) is equal to this mean slope. For this problem, there are two values of c that work. The smaller one is= and the larger one is= i found the mean slope=3 but cannot get the values where f'(c) is equal to 3.... tried setting the derivative equal to three but that doesnt yield the right answer, or im not working it out right....please

  • one year ago
  • one year ago

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  1. ksaimouli
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    u mena find the equation of tangent line?

    • one year ago
  2. ksaimouli
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    |dw:1353882845431:dw|

    • one year ago
  3. gnarballs
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    i dont think so... i need to find where f' is = to the mean slope(3) on the interval (-2,2)..tried setting f' =3 but with no luck

    • one year ago
  4. ksaimouli
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    ok it means the same ok so use the formula above

    • one year ago
  5. ksaimouli
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    find derivative first

    • one year ago
  6. ksaimouli
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    what did u get

    • one year ago
  7. gnarballs
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    6x^2-5

    • one year ago
  8. ksaimouli
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    now calculate |dw:1353883173646:dw|

    • one year ago
  9. gnarballs
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    its 3

    • one year ago
  10. ksaimouli
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    set the derivative=3 solve for x

    • one year ago
  11. gnarballs
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    awesome, found my mistake...thank you man

    • one year ago
  12. ksaimouli
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    what did u get?

    • one year ago
  13. gnarballs
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    -1.1545, 1.1545

    • one year ago
  14. ksaimouli
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    yup u got it yup

    • one year ago
  15. ksaimouli
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    anymore question>

    • one year ago
  16. gnarballs
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    yes .. (1 pt) Consider the function f(x) = 1/x on the interval [ 1 , 10 ]. (A) Find the average or mean slope of the function on this interval. - i found it to be -.1 (B) By the Mean Value Theorem, we know there exists a c in the open interval ( 1 , 10 ) such that f'( c) is equal to this mean slope. Find all values of c that work and list them (separated by commas) in the box below. - i set -1/x^2 = -.1 and got -3.1622 and 3.1622 but it doesnt accept those as answers

    • one year ago
  17. ksaimouli
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    yup

    • one year ago
  18. ksaimouli
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    correct

    • one year ago
  19. gnarballs
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    ok i had to use only the positive one since it was in the interval given........thank you for your help..... have an awesome day !

    • one year ago
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