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ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1353885456771:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
\[\ln(12x)^3\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
@ivanmlerner
 one year ago

ivanmlerner Group TitleBest ResponseYou've already chosen the best response.1
You need to use the chain rule here. ln is one function, something^3 another and 12x another.
 one year ago

ivanmlerner Group TitleBest ResponseYou've already chosen the best response.1
Do you have any ideas on what the first step is?
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1353887083835:dw
 one year ago

ivanmlerner Group TitleBest ResponseYou've already chosen the best response.1
Almost, you forgot to derivate the function z^3. You did the derivative of the ln and the one inside the cubic power.
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
so should i take derivative (12x)^3 i thought i should only take derivative of inside the ()^3
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1353888159532:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1353888193965:dw
 one year ago

ivanmlerner Group TitleBest ResponseYou've already chosen the best response.1
Now that is correct. Just to summarize you have the following:\[f(x)=\ln(x)\]\[g(x)=x^3\]\[h(x)=12x\]and you want\[\frac{df(g(h(x)))}{dx}=\frac{df}{dg}\frac{dg}{dh}\frac{dh}{dx}\]\[\frac{df}{dg}=\frac{1}{g}=\frac{1}{(12x)^3}\]\[\frac{dg}{dh}=3h^2=3(12x)^2\]\[\frac{dh}{dx}=2\]
 one year ago
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