A community for students.
Here's the question you clicked on:
 0 viewing
ksaimouli
 3 years ago
derivative
ksaimouli
 3 years ago
derivative

This Question is Closed

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1353885456771:dw

ivanmlerner
 3 years ago
Best ResponseYou've already chosen the best response.1You need to use the chain rule here. ln is one function, something^3 another and 12x another.

ivanmlerner
 3 years ago
Best ResponseYou've already chosen the best response.1Do you have any ideas on what the first step is?

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1353887083835:dw

ivanmlerner
 3 years ago
Best ResponseYou've already chosen the best response.1Almost, you forgot to derivate the function z^3. You did the derivative of the ln and the one inside the cubic power.

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0so should i take derivative (12x)^3 i thought i should only take derivative of inside the ()^3

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1353888159532:dw

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1353888193965:dw

ivanmlerner
 3 years ago
Best ResponseYou've already chosen the best response.1Now that is correct. Just to summarize you have the following:\[f(x)=\ln(x)\]\[g(x)=x^3\]\[h(x)=12x\]and you want\[\frac{df(g(h(x)))}{dx}=\frac{df}{dg}\frac{dg}{dh}\frac{dh}{dx}\]\[\frac{df}{dg}=\frac{1}{g}=\frac{1}{(12x)^3}\]\[\frac{dg}{dh}=3h^2=3(12x)^2\]\[\frac{dh}{dx}=2\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.