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swin2013

  • 3 years ago

Conical Problem?

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  1. swin2013
    • 3 years ago
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    I got \[\pi/9 * 3^{2} *-12\]

  2. swin2013
    • 3 years ago
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    so far

  3. swin2013
    • 3 years ago
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    @zepdrix

  4. zepdrix
    • 3 years ago
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    It's telling me to log in to view the document :c that's too much work for me lol

  5. swin2013
    • 3 years ago
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    really?? it didn't for me? I'll just type it out lol

  6. swin2013
    • 3 years ago
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    Water is draining from a conical tank with height 12 feet and diameter 8 feet into cylindrical tank that has a base with area 400pi square feet. The depth h, in feet, of the water in the conical tank is changing at the rate of (h-12) feet per minute. (The volume V of a cone with radius r and height h is V = 1/3pir^2*h). a) Write an expression for the volume of water in the conical tank as a function of h. b) At what rate is the volume of water in the conical tank changing when h = 3? Indicate units of measure for a) i got \[\frac{ \pi }{ 27 } h ^{3}\] and b) i got 9pi ft/min

  7. zepdrix
    • 3 years ago
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    Crap sorry I gotta :C I'll come take a look at it in a little bit if someone hasn't helped you by then c:

  8. swin2013
    • 3 years ago
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    |dw:1353891937691:dw|

  9. swin2013
    • 3 years ago
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    lol alright thanks :)

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