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JenniferSmart1
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I did this problem a month ago and I somewhat forgot how to do it.
 one year ago
 one year ago
JenniferSmart1 Group Title
I did this problem a month ago and I somewhat forgot how to do it.
 one year ago
 one year ago

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JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
the third line where n=2. How did we determine that it can be written as... \[\frac{C_0}{1\cdot2\cdot3\cdot4}\]
 one year ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.0
Is that Taylor series or something? D:
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
no not really the original function is \[C_{n+2}=\frac{C_n}{(n+2)(n+1)}\]
 one year ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.0
Sorry. This goes over my dumb head. :'( Math gods like @satellite73 @amistre64 @asnaseer can help you with problems like these. :/
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
I'm sure @UnkleRhaukus can help...where is he?
 one year ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.0
@eseidl @eSpeX can you guys solve this? Last time I saw Rhau in chem section.
 one year ago

eseidl Group TitleBest ResponseYou've already chosen the best response.2
Am I missing something? Isn't it just:\[C_{n+2}=\frac{c_n}{(n+2)(n+1)}\]Input n=2\[C_{2+2}=\frac{c_2}{(2+2)(2+1)}\]So,\[C_4=\frac{c_2}{4*3}\]But we know\[c_2=\frac{c_0}{1*2}\]From the table where n=0.Thus:\[C_4=\frac{c_0}{4*3*2*1}=\frac{c_0}{4!}\]
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
yeah I think you're right, Thanks!
 one year ago

eseidl Group TitleBest ResponseYou've already chosen the best response.2
lol, yeah it just seemed too straight forward to call in the "math gods" (which I definitely am not one of lol)
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
It is straight forward I know...LOL and Turing has taught me how to do this...I just forgot
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
I guess doing math and watching The Walking Dead can prevent one from doing simple math ;P
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
@eseidl all you missing is the negative signs cancel \[n=2\qquad C_4=\frac{C_2}{4\cdot3}=\frac{\tfrac{C_0}{2\cdot1}}{4\cdot3}=\frac{C_0}{4\cdot3\cdot 2\cdot1}=\frac{C_0}{4!}\],
 one year ago

eseidl Group TitleBest ResponseYou've already chosen the best response.2
@UnkleRhaukus oooops, yeah good call :)
 one year ago
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