itsjustme_lol
Write the equation of the line with a slope of -1/3 and passing through the point (6, -4).
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surdawi
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y-y1=m(x-x1)
itsjustme_lol
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wait im confused to what that is?
surdawi
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m is the slope and x1,y1 the point u have
itsjustme_lol
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im not exactly understanding..."/
surdawi
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what is the slope?
itsjustme_lol
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-1/3
surdawi
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ok plug that into
y-y1=m(x-x1)
now what is the x and y values?
itsjustme_lol
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0,3?
MathLegend
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In that formula..
m = slope
MathLegend
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@itsjustme_lol can you plug in everything into that formula now?
itsjustme_lol
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so m=-1/3
MathLegend
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Right.... and you know what x1 and y1 are since they gave you the coordinates. So plug it in....
y-y1=m(x-x1)
itsjustme_lol
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y-4=m(x-6)?
MathLegend
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y-(-4)=-1/3(x-6)
y+4=-1/3(x-6)
@itsjustme_lol do you understand that?
itsjustme_lol
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why did we put +4 in the second one?
MathLegend
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y-(-4) = y+4
MathLegend
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two negatives makes a positive
MathLegend
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It is a negative being multiplied by a negative. That is something you should be familiar with.
MathLegend
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y+4=-1/3(x-6)
Can you simplify the right side of this equation?
itsjustme_lol
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give me a second
itsjustme_lol
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wait im still confused. im sorry!!!
MathLegend
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It is fine.
MathLegend
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What are you confused about?
itsjustme_lol
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i dont know how to solve that equation
MathLegend
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y+4=-1/3(x-6)
*We must first distribute that -1/3 on the right side of the equation.
y+4=-1/3x+2
Now we need to make this equation into the slope-intercept form... so y=mx+b... so lets subtract the 4 from both sides.
y+4=-1/3x+2
-4 -4
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y=-1/3x-2
MathLegend
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@itsjustme_lol do you understand?
itsjustme_lol
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that makes sense now