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Write the equation of the line with a slope of -1/3 and passing through the point (6, -4).

Mathematics
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y-y1=m(x-x1)
wait im confused to what that is?
m is the slope and x1,y1 the point u have

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Other answers:

im not exactly understanding..."/
what is the slope?
-1/3
ok plug that into y-y1=m(x-x1) now what is the x and y values?
0,3?
In that formula.. m = slope
@itsjustme_lol can you plug in everything into that formula now?
so m=-1/3
Right.... and you know what x1 and y1 are since they gave you the coordinates. So plug it in.... y-y1=m(x-x1)
y-4=m(x-6)?
y-(-4)=-1/3(x-6) y+4=-1/3(x-6) @itsjustme_lol do you understand that?
why did we put +4 in the second one?
y-(-4) = y+4
two negatives makes a positive
It is a negative being multiplied by a negative. That is something you should be familiar with.
y+4=-1/3(x-6) Can you simplify the right side of this equation?
give me a second
wait im still confused. im sorry!!!
It is fine.
What are you confused about?
i dont know how to solve that equation
y+4=-1/3(x-6) *We must first distribute that -1/3 on the right side of the equation. y+4=-1/3x+2 Now we need to make this equation into the slope-intercept form... so y=mx+b... so lets subtract the 4 from both sides. y+4=-1/3x+2 -4 -4 --------------------- y=-1/3x-2
@itsjustme_lol do you understand?
that makes sense now

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