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pratu043 Group Title

ABCD is a quadrilateral where AB is parallel to DC. If x = (4y)/3 and y = (3z)/8 find x, y, and z.

  • one year ago
  • one year ago

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  1. pratu043 Group Title
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    |dw:1353909972372:dw|

    • one year ago
  2. darthjavier Group Title
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    \[\angle A+\angle D=180^\circ\\\angle B + \angle C=180^\circ\] Try to solve it now :)

    • one year ago
  3. pratu043 Group Title
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    I tried but I'm getting z as more than 90 degrees.

    • one year ago
  4. pratu043 Group Title
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    z is an acute angle isn't it?

    • one year ago
  5. pratu043 Group Title
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    z + y = 180 and \[y = \frac{ 3z }{ 8 }\] \[z + \frac{ 3z }{ 8 } = 180\] \[\frac{ 8z + 3z }{ 8 } = 180\] \[\frac{ 11z }{ 8 } = 180\] \[z = \frac{ 180\times8 }{ 11 }\]

    • one year ago
  6. pratu043 Group Title
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    I don't think that's right.

    • one year ago
  7. darthjavier Group Title
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    Go ahead, you are right. Try to put z instead of y in your graph ;)

    • one year ago
  8. pratu043 Group Title
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    What do you mean 'in your graph'?

    • one year ago
  9. geoffb Group Title
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    if y = 3/8 of z, it will be smaller than z. Are you sure you have y and z labelled correctly?

    • one year ago
  10. pratu043 Group Title
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    Yes. You think it could be a printing mistake?

    • one year ago
  11. geoffb Group Title
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    No clue, but if z is acute, and y is 3/8 of z, then there's no way y can be obtuse.

    • one year ago
  12. pratu043 Group Title
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    Yeah, I never thought of that.

    • one year ago
  13. darthjavier Group Title
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    Sorry, graphic*. I mean that you have the wrong graphic or wrong data.

    • one year ago
  14. pratu043 Group Title
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    The answers given are 96, 96 and 84.

    • one year ago
  15. geoffb Group Title
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    Try it the other way around. z = 3y/8

    • one year ago
  16. geoffb Group Title
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    Then you get 11y/8 = 180

    • one year ago
  17. geoffb Group Title
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    \(y = \frac{180 \times 8}{11}\)

    • one year ago
  18. geoffb Group Title
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    That gives an angle of 131, meaning z would be 49. Doesn't work.

    • one year ago
  19. geoffb Group Title
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    Well, it works, but not to the answers you're given. :)

    • one year ago
  20. pratu043 Group Title
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    yes.

    • one year ago
  21. pratu043 Group Title
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    I already tried all that.

    • one year ago
  22. pratu043 Group Title
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    Well, thanks for your help anyway. I'll ask my maths teacher.

    • one year ago
  23. geoffb Group Title
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    No problem. :)

    • one year ago
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