## pratu043 Group Title ABCD is a quadrilateral where AB is parallel to DC. If x = (4y)/3 and y = (3z)/8 find x, y, and z. one year ago one year ago

1. pratu043 Group Title

|dw:1353909972372:dw|

2. darthjavier Group Title

$\angle A+\angle D=180^\circ\\\angle B + \angle C=180^\circ$ Try to solve it now :)

3. pratu043 Group Title

I tried but I'm getting z as more than 90 degrees.

4. pratu043 Group Title

z is an acute angle isn't it?

5. pratu043 Group Title

z + y = 180 and $y = \frac{ 3z }{ 8 }$ $z + \frac{ 3z }{ 8 } = 180$ $\frac{ 8z + 3z }{ 8 } = 180$ $\frac{ 11z }{ 8 } = 180$ $z = \frac{ 180\times8 }{ 11 }$

6. pratu043 Group Title

I don't think that's right.

7. darthjavier Group Title

8. pratu043 Group Title

What do you mean 'in your graph'?

9. geoffb Group Title

if y = 3/8 of z, it will be smaller than z. Are you sure you have y and z labelled correctly?

10. pratu043 Group Title

Yes. You think it could be a printing mistake?

11. geoffb Group Title

No clue, but if z is acute, and y is 3/8 of z, then there's no way y can be obtuse.

12. pratu043 Group Title

Yeah, I never thought of that.

13. darthjavier Group Title

Sorry, graphic*. I mean that you have the wrong graphic or wrong data.

14. pratu043 Group Title

The answers given are 96, 96 and 84.

15. geoffb Group Title

Try it the other way around. z = 3y/8

16. geoffb Group Title

Then you get 11y/8 = 180

17. geoffb Group Title

$$y = \frac{180 \times 8}{11}$$

18. geoffb Group Title

That gives an angle of 131, meaning z would be 49. Doesn't work.

19. geoffb Group Title

Well, it works, but not to the answers you're given. :)

20. pratu043 Group Title

yes.

21. pratu043 Group Title