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swissgirl Group TitleBest ResponseYou've already chosen the best response.0
dw:1353910548451:dw
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
You need to use integration by parts
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
put u= y^2/2 then.
 2 years ago

ivanmlerner Group TitleBest ResponseYou've already chosen the best response.0
Is it:\[\int\limits\limits_{\infty}^{\infty}ke^{\frac{y^2}{2}}dy=1\]?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
u= y^2/2 find dy =... ?
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
I used u=y^2
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
but maybe its easier with u=y^2/2
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
Its not smart to have that negative there
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
Do you agree?
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
@hartnn ?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
oh, sorry.... yeah, its easier with e^u constants can be rearranged easily...
 2 years ago

ivanmlerner Group TitleBest ResponseYou've already chosen the best response.0
I got the wrong answer when evaluating the integral, and I won't do it again now. But this function is a gaussian, and it is expected that the constant k in this case has the value 1/sqrt(2pi)=sqrt(2pi)/2pi. That comes from the statistic theory.
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
Yes the answer is 1/ sqrt(2*pi) I just so dont follow how they got that answer.
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
did u try that substitution and then integration by parts ?
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
I was getting weird answers. I have not really touched calculus for over a yr so i cld be messing up
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
\(\huge\int \frac{e^{u}u^{1/2}}{\sqrt2}du\) when 2u=y^2 yes, its messy...
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
How would you continue from here?
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
Can you show me?
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
ok dont show me
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
u need to know gamma function to solve that ... i am so sorry, my internet are giving me connection problems....
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
hmmm I know the gamma distribution function
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
ohhhh I see it now lol
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
\( \Gamma(z) = \int_0^\infty e^{t} t^{z1} dt \)
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
Yesssssss
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
now , you'll get it easily.
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
ask if u don't get...
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
Thanks let me try to work it out then. Thanks :)))))
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
\(\Gamma{1/2} = \sqrt{\pi}\)
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
you'll need it.
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
ohhh coool never knew that
 2 years ago

swissgirl Group TitleBest ResponseYou've already chosen the best response.0
I feel like i am missing the basics in math :(
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
http://en.wikipedia.org/wiki/Gamma_function
 2 years ago
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