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swissgirl
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1353910548451:dw

swissgirl
 2 years ago
Best ResponseYou've already chosen the best response.0You need to use integration by parts

ivanmlerner
 2 years ago
Best ResponseYou've already chosen the best response.0Is it:\[\int\limits\limits_{\infty}^{\infty}ke^{\frac{y^2}{2}}dy=1\]?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1u= y^2/2 find dy =... ?

swissgirl
 2 years ago
Best ResponseYou've already chosen the best response.0but maybe its easier with u=y^2/2

swissgirl
 2 years ago
Best ResponseYou've already chosen the best response.0Its not smart to have that negative there

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1oh, sorry.... yeah, its easier with e^u constants can be rearranged easily...

ivanmlerner
 2 years ago
Best ResponseYou've already chosen the best response.0I got the wrong answer when evaluating the integral, and I won't do it again now. But this function is a gaussian, and it is expected that the constant k in this case has the value 1/sqrt(2pi)=sqrt(2pi)/2pi. That comes from the statistic theory.

swissgirl
 2 years ago
Best ResponseYou've already chosen the best response.0Yes the answer is 1/ sqrt(2*pi) I just so dont follow how they got that answer.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1did u try that substitution and then integration by parts ?

swissgirl
 2 years ago
Best ResponseYou've already chosen the best response.0I was getting weird answers. I have not really touched calculus for over a yr so i cld be messing up

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1\(\huge\int \frac{e^{u}u^{1/2}}{\sqrt2}du\) when 2u=y^2 yes, its messy...

swissgirl
 2 years ago
Best ResponseYou've already chosen the best response.0How would you continue from here?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1u need to know gamma function to solve that ... i am so sorry, my internet are giving me connection problems....

swissgirl
 2 years ago
Best ResponseYou've already chosen the best response.0hmmm I know the gamma distribution function

swissgirl
 2 years ago
Best ResponseYou've already chosen the best response.0ohhhh I see it now lol

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1\( \Gamma(z) = \int_0^\infty e^{t} t^{z1} dt \)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1now , you'll get it easily.

swissgirl
 2 years ago
Best ResponseYou've already chosen the best response.0Thanks let me try to work it out then. Thanks :)))))

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1\(\Gamma{1/2} = \sqrt{\pi}\)

swissgirl
 2 years ago
Best ResponseYou've already chosen the best response.0ohhh coool never knew that

swissgirl
 2 years ago
Best ResponseYou've already chosen the best response.0I feel like i am missing the basics in math :(
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