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swissgirlBest ResponseYou've already chosen the best response.0
dw:1353910548451:dw
 one year ago

swissgirlBest ResponseYou've already chosen the best response.0
You need to use integration by parts
 one year ago

ivanmlernerBest ResponseYou've already chosen the best response.0
Is it:\[\int\limits\limits_{\infty}^{\infty}ke^{\frac{y^2}{2}}dy=1\]?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
u= y^2/2 find dy =... ?
 one year ago

swissgirlBest ResponseYou've already chosen the best response.0
but maybe its easier with u=y^2/2
 one year ago

swissgirlBest ResponseYou've already chosen the best response.0
Its not smart to have that negative there
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
oh, sorry.... yeah, its easier with e^u constants can be rearranged easily...
 one year ago

ivanmlernerBest ResponseYou've already chosen the best response.0
I got the wrong answer when evaluating the integral, and I won't do it again now. But this function is a gaussian, and it is expected that the constant k in this case has the value 1/sqrt(2pi)=sqrt(2pi)/2pi. That comes from the statistic theory.
 one year ago

swissgirlBest ResponseYou've already chosen the best response.0
Yes the answer is 1/ sqrt(2*pi) I just so dont follow how they got that answer.
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
did u try that substitution and then integration by parts ?
 one year ago

swissgirlBest ResponseYou've already chosen the best response.0
I was getting weird answers. I have not really touched calculus for over a yr so i cld be messing up
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(\huge\int \frac{e^{u}u^{1/2}}{\sqrt2}du\) when 2u=y^2 yes, its messy...
 one year ago

swissgirlBest ResponseYou've already chosen the best response.0
How would you continue from here?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
u need to know gamma function to solve that ... i am so sorry, my internet are giving me connection problems....
 one year ago

swissgirlBest ResponseYou've already chosen the best response.0
hmmm I know the gamma distribution function
 one year ago

swissgirlBest ResponseYou've already chosen the best response.0
ohhhh I see it now lol
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\( \Gamma(z) = \int_0^\infty e^{t} t^{z1} dt \)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
now , you'll get it easily.
 one year ago

swissgirlBest ResponseYou've already chosen the best response.0
Thanks let me try to work it out then. Thanks :)))))
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(\Gamma{1/2} = \sqrt{\pi}\)
 one year ago

swissgirlBest ResponseYou've already chosen the best response.0
ohhh coool never knew that
 one year ago

swissgirlBest ResponseYou've already chosen the best response.0
I feel like i am missing the basics in math :(
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
http://en.wikipedia.org/wiki/Gamma_function
 one year ago
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