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PLEAAASSEEE help Pre Calc:
thank you so much picture posted below
xoxo vvv
 one year ago
 one year ago
PLEAAASSEEE help Pre Calc: thank you so much picture posted below xoxo vvv
 one year ago
 one year ago

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jim_thompson5910Best ResponseYou've already chosen the best response.1
you first have to use the pythagorean theorem to find the length of AB
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
AC^2 + BC^2 = AB^2 36^2 + 24^2 = x^2 1296 + 576 = x^2 keep going to solve for x
 one year ago

samalamiBest ResponseYou've already chosen the best response.0
x=+/ 12 to the power of 13
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
you mean \[\Large x = \pm 12\sqrt{13}\] right?
 one year ago

samalamiBest ResponseYou've already chosen the best response.0
yes :) @jim_thompson5910
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
since AB is the length and x is the length, we only consider positive lengths so \[\Large x = 12\sqrt{13}\] which means \[\Large AB = 12\sqrt{13}\]
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
now use the definition of sine, plug in the lengths, and simplify sin(angle) = opposite/hypotenuse sin(A) = 24/(12*sqrt(13)) sin(A) = 2/(sqrt(13)) sin(A) = (2*sqrt(13))/(sqrt(13)*sqrt(13)) sin(A) = (2*sqrt(13))/(13)
 one year ago

samalamiBest ResponseYou've already chosen the best response.0
ughhh thank you so much! FINALLY I understand this nonsense.
 one year ago
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