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samalami

  • 2 years ago

PLEAAASSEEE help Pre Calc: thank you so much picture posted below xoxo vvv

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  1. samalami
    • 2 years ago
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  2. jim_thompson5910
    • 2 years ago
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    you first have to use the pythagorean theorem to find the length of AB

  3. jim_thompson5910
    • 2 years ago
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    AC^2 + BC^2 = AB^2 36^2 + 24^2 = x^2 1296 + 576 = x^2 keep going to solve for x

  4. samalami
    • 2 years ago
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    x=+/- 12 to the power of 13

  5. samalami
    • 2 years ago
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    @jim_thompson5910

  6. jim_thompson5910
    • 2 years ago
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    you mean \[\Large x = \pm 12\sqrt{13}\] right?

  7. samalami
    • 2 years ago
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    yes :) @jim_thompson5910

  8. jim_thompson5910
    • 2 years ago
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    since AB is the length and x is the length, we only consider positive lengths so \[\Large x = 12\sqrt{13}\] which means \[\Large AB = 12\sqrt{13}\]

  9. jim_thompson5910
    • 2 years ago
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    now use the definition of sine, plug in the lengths, and simplify sin(angle) = opposite/hypotenuse sin(A) = 24/(12*sqrt(13)) sin(A) = 2/(sqrt(13)) sin(A) = (2*sqrt(13))/(sqrt(13)*sqrt(13)) sin(A) = (2*sqrt(13))/(13)

  10. samalami
    • 2 years ago
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    ughhh thank you so much! FINALLY I understand this nonsense.

  11. jim_thompson5910
    • 2 years ago
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    that's great

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