A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1you first have to use the pythagorean theorem to find the length of AB

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1AC^2 + BC^2 = AB^2 36^2 + 24^2 = x^2 1296 + 576 = x^2 keep going to solve for x

samalami
 2 years ago
Best ResponseYou've already chosen the best response.0x=+/ 12 to the power of 13

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1you mean \[\Large x = \pm 12\sqrt{13}\] right?

samalami
 2 years ago
Best ResponseYou've already chosen the best response.0yes :) @jim_thompson5910

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1since AB is the length and x is the length, we only consider positive lengths so \[\Large x = 12\sqrt{13}\] which means \[\Large AB = 12\sqrt{13}\]

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.1now use the definition of sine, plug in the lengths, and simplify sin(angle) = opposite/hypotenuse sin(A) = 24/(12*sqrt(13)) sin(A) = 2/(sqrt(13)) sin(A) = (2*sqrt(13))/(sqrt(13)*sqrt(13)) sin(A) = (2*sqrt(13))/(13)

samalami
 2 years ago
Best ResponseYou've already chosen the best response.0ughhh thank you so much! FINALLY I understand this nonsense.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.