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samalami
PLEAAASSEEE help Pre Calc: thank you so much picture posted below xoxo vvv
you first have to use the pythagorean theorem to find the length of AB
AC^2 + BC^2 = AB^2 36^2 + 24^2 = x^2 1296 + 576 = x^2 keep going to solve for x
x=+/- 12 to the power of 13
you mean \[\Large x = \pm 12\sqrt{13}\] right?
yes :) @jim_thompson5910
since AB is the length and x is the length, we only consider positive lengths so \[\Large x = 12\sqrt{13}\] which means \[\Large AB = 12\sqrt{13}\]
now use the definition of sine, plug in the lengths, and simplify sin(angle) = opposite/hypotenuse sin(A) = 24/(12*sqrt(13)) sin(A) = 2/(sqrt(13)) sin(A) = (2*sqrt(13))/(sqrt(13)*sqrt(13)) sin(A) = (2*sqrt(13))/(13)
ughhh thank you so much! FINALLY I understand this nonsense.