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anonymous
 4 years ago
can someone please help Pre calc please??
It's A, B, C, or D
picture attached vvv
xoxo
anonymous
 4 years ago
can someone please help Pre calc please?? It's A, B, C, or D picture attached vvv xoxo

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Use pythagorean theorem to get your third side, then use triangular trig ratios to get the trig functions... like sin(theta)=opp/hyp, cos(theta)=adj/hyp, etc...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0There is a nice little short cut too... once you find sin, cos, and tan... csc, sec, and cot are the reciprocals.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@EulerGroupie is it A then??? the first choice?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That is not what I got. What did you get for the missing side?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0eek!\[c ^{2}=a ^{2}+b ^{2}\]where c is the hypotenuse. You have c and a... solve for b\[b=\sqrt{c ^{2}a ^{2}}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It comes out nice... not irrational. What do you get for the missing side now?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now, all of those trig functions have angle A in them... so you are looking at the triangle from that corner. If that's the case, then 9 is your adjacent side, 12 is your opposite side, and 15 is the hypotenuse. So what is sin A=opp/hyp?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes! Now cos A=adj/hyp... which is?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Not what I got. adj=9, hyp=15...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what is the equation for tan?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you, I understand the rest now

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Awesome! You're welcome.
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