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samalami

  • 2 years ago

can someone please help Pre calc please?? It's A, B, C, or D picture attached vvv xoxo

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  1. samalami
    • 2 years ago
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  2. EulerGroupie
    • 2 years ago
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    Use pythagorean theorem to get your third side, then use triangular trig ratios to get the trig functions... like sin(theta)=opp/hyp, cos(theta)=adj/hyp, etc...

  3. EulerGroupie
    • 2 years ago
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    There is a nice little short cut too... once you find sin, cos, and tan... csc, sec, and cot are the reciprocals.

  4. samalami
    • 2 years ago
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    @EulerGroupie is it A then??? the first choice?

  5. EulerGroupie
    • 2 years ago
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    That is not what I got. What did you get for the missing side?

  6. samalami
    • 2 years ago
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    12/3sqrt41

  7. EulerGroupie
    • 2 years ago
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    eek!\[c ^{2}=a ^{2}+b ^{2}\]where c is the hypotenuse. You have c and a... solve for b\[b=\sqrt{c ^{2}-a ^{2}}\]

  8. EulerGroupie
    • 2 years ago
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    It comes out nice... not irrational. What do you get for the missing side now?

  9. samalami
    • 2 years ago
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    9?

  10. EulerGroupie
    • 2 years ago
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    Yes

  11. EulerGroupie
    • 2 years ago
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    Now, all of those trig functions have angle A in them... so you are looking at the triangle from that corner. If that's the case, then 9 is your adjacent side, 12 is your opposite side, and 15 is the hypotenuse. So what is sin A=opp/hyp?

  12. samalami
    • 2 years ago
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    4/5

  13. EulerGroupie
    • 2 years ago
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    Yes! Now cos A=adj/hyp... which is?

  14. samalami
    • 2 years ago
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    3/4

  15. samalami
    • 2 years ago
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    sorry thats not it!!

  16. EulerGroupie
    • 2 years ago
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    Not what I got. adj=9, hyp=15...

  17. samalami
    • 2 years ago
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    3/5

  18. EulerGroupie
    • 2 years ago
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    Yes! tan?

  19. samalami
    • 2 years ago
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    what is the equation for tan?

  20. EulerGroupie
    • 2 years ago
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    opp/adj

  21. samalami
    • 2 years ago
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    4/3 :)

  22. EulerGroupie
    • 2 years ago
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    Yes!

  23. samalami
    • 2 years ago
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    thank you, I understand the rest now

  24. EulerGroupie
    • 2 years ago
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    Awesome! You're welcome.

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