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anonymous
 3 years ago
So, on my right triangle triangle I have here, they give all the sides and are asking for an angle
The sides are
Opp=15
Adj=8
Hyp=17
And we are looking for the x angle.
anonymous
 3 years ago
So, on my right triangle triangle I have here, they give all the sides and are asking for an angle The sides are Opp=15 Adj=8 Hyp=17 And we are looking for the x angle.

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do you know SOHCAHTOA? Your sine, cosine, and tangent laws?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay, since you know all three side lengths, you can use any of the three functions to determine x.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0For example, \(\sin x = \frac{\text{opp}}{\text{hyp}}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0And that is it? Just use 17 over 15 ,divide and my answer would be 1.13?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It's not x = 1.13. It's sin x = 1.13.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ah, sorry for not using correct mathematical vocabulary.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No, that's not my point. The point is, you need to solve for x. Right now, you only know sin x.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You need to get rid of the sin.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh? How is this done?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0One thing first. It's not 17/15, it's 15/17.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So, \(\sin x = \frac{15}{17} = 0.882\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0To get rid of the sin, you calculate \(\sin^{1}\). On your calculator, you should have a way to do this.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So, \(x = \sin^{1} (\frac{15}{17})\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I did not know there was such an option? Thank you.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You might need to hit something like 2nd function, or inverse, then hit sin.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You should end up with something around 60 degrees, if it's sine of 15/17.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0This isn't my outcome, I get a decimal of 1.001

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay, so you took your amount (0.882) and hit inverse sine (sin^1) and got 1.001?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh but wait, that is sin(h), Sorry, personal mistake.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Since you knew all the sides, you could have also done \(x = \cos^{1} (\frac{8}{17})\) or \(x = \tan^{1} (\frac{15}{8})\), and gotten identical answers.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Odd, I get the decimal of 0.795, how does this lead to 60 degrees?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What calculation gives you 0.795?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well, seeing as I'm using the computer based calculator, this may have swayed my calculation. When typed in, it shows up as *asinh(15 /17)*

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Where did you type that in?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But lo, I have found my answer as you have predicted, thank you so much kind sir, It was simply a typing error.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Good stuff! You're very welcome. :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I shall be on my way! Good day to you, and thank you for your time.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You too, David! Cheers!
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