kennedav000
So, on my right triangle triangle I have here, they give all the sides and are asking for an angle
The sides are
Opp=15
Adj=8
Hyp=17
And we are looking for the x angle.
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geoffb
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Do you know SOHCAHTOA?
Your sine, cosine, and tangent laws?
kennedav000
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Yes
geoffb
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Okay, since you know all three side lengths, you can use any of the three functions to determine x.
geoffb
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For example, \(\sin x = \frac{\text{opp}}{\text{hyp}}\)
kennedav000
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And that is it? Just use 17 over 15 ,divide and my answer would be 1.13?
geoffb
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It's not x = 1.13. It's sin x = 1.13.
kennedav000
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Ah, sorry for not using correct mathematical vocabulary.
geoffb
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No, that's not my point. The point is, you need to solve for x. Right now, you only know sin x.
geoffb
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You need to get rid of the sin.
kennedav000
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Oh? How is this done?
geoffb
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One thing first. It's not 17/15, it's 15/17.
kennedav000
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Got it
geoffb
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So, \(\sin x = \frac{15}{17} = 0.882\)
geoffb
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To get rid of the sin, you calculate \(\sin^{-1}\). On your calculator, you should have a way to do this.
geoffb
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So, \(x = \sin^{-1} (\frac{15}{17})\)
kennedav000
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I did not know there was such an option? Thank you.
geoffb
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You might need to hit something like 2nd function, or inverse, then hit sin.
geoffb
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You should end up with something around 60 degrees, if it's sine of 15/17.
kennedav000
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This isn't my outcome, I get a decimal of 1.001
geoffb
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Okay, so you took your amount (0.882) and hit inverse sine (sin^-1) and got 1.001?
kennedav000
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Oh but wait, that is sin(h), Sorry, personal mistake.
geoffb
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No worries.
geoffb
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Since you knew all the sides, you could have also done \(x = \cos^{-1} (\frac{8}{17})\) or \(x = \tan^{-1} (\frac{15}{8})\), and gotten identical answers.
kennedav000
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Odd, I get the decimal of 0.795, how does this lead to 60 degrees?
geoffb
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What calculation gives you 0.795?
kennedav000
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Well, seeing as I'm using the computer based calculator, this may have swayed my calculation. When typed in, it shows up as *asinh(15 /17)*
geoffb
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Where did you type that in?
kennedav000
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But lo, I have found my answer as you have predicted, thank you so much kind sir, It was simply a typing error.
geoffb
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Good stuff! You're very welcome. :)
kennedav000
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I shall be on my way! Good day to you, and thank you for your time.
geoffb
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You too, David! Cheers!