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kennedav000 Group Title

So, on my right triangle triangle I have here, they give all the sides and are asking for an angle The sides are Opp=15 Adj=8 Hyp=17 And we are looking for the x angle.

  • one year ago
  • one year ago

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  1. geoffb Group Title
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    Do you know SOHCAHTOA? Your sine, cosine, and tangent laws?

    • one year ago
  2. kennedav000 Group Title
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    Yes

    • one year ago
  3. geoffb Group Title
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    Okay, since you know all three side lengths, you can use any of the three functions to determine x.

    • one year ago
  4. geoffb Group Title
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    For example, \(\sin x = \frac{\text{opp}}{\text{hyp}}\)

    • one year ago
  5. kennedav000 Group Title
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    And that is it? Just use 17 over 15 ,divide and my answer would be 1.13?

    • one year ago
  6. geoffb Group Title
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    It's not x = 1.13. It's sin x = 1.13.

    • one year ago
  7. kennedav000 Group Title
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    Ah, sorry for not using correct mathematical vocabulary.

    • one year ago
  8. geoffb Group Title
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    No, that's not my point. The point is, you need to solve for x. Right now, you only know sin x.

    • one year ago
  9. geoffb Group Title
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    You need to get rid of the sin.

    • one year ago
  10. kennedav000 Group Title
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    Oh? How is this done?

    • one year ago
  11. geoffb Group Title
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    One thing first. It's not 17/15, it's 15/17.

    • one year ago
  12. kennedav000 Group Title
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    Got it

    • one year ago
  13. geoffb Group Title
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    So, \(\sin x = \frac{15}{17} = 0.882\)

    • one year ago
  14. geoffb Group Title
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    To get rid of the sin, you calculate \(\sin^{-1}\). On your calculator, you should have a way to do this.

    • one year ago
  15. geoffb Group Title
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    So, \(x = \sin^{-1} (\frac{15}{17})\)

    • one year ago
  16. kennedav000 Group Title
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    I did not know there was such an option? Thank you.

    • one year ago
  17. geoffb Group Title
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    You might need to hit something like 2nd function, or inverse, then hit sin.

    • one year ago
  18. geoffb Group Title
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    You should end up with something around 60 degrees, if it's sine of 15/17.

    • one year ago
  19. kennedav000 Group Title
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    This isn't my outcome, I get a decimal of 1.001

    • one year ago
  20. geoffb Group Title
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    Okay, so you took your amount (0.882) and hit inverse sine (sin^-1) and got 1.001?

    • one year ago
  21. kennedav000 Group Title
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    Oh but wait, that is sin(h), Sorry, personal mistake.

    • one year ago
  22. geoffb Group Title
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    No worries.

    • one year ago
  23. geoffb Group Title
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    Since you knew all the sides, you could have also done \(x = \cos^{-1} (\frac{8}{17})\) or \(x = \tan^{-1} (\frac{15}{8})\), and gotten identical answers.

    • one year ago
  24. kennedav000 Group Title
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    Odd, I get the decimal of 0.795, how does this lead to 60 degrees?

    • one year ago
  25. geoffb Group Title
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    What calculation gives you 0.795?

    • one year ago
  26. kennedav000 Group Title
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    Well, seeing as I'm using the computer based calculator, this may have swayed my calculation. When typed in, it shows up as *asinh(15 /17)*

    • one year ago
  27. geoffb Group Title
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    Where did you type that in?

    • one year ago
  28. kennedav000 Group Title
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    But lo, I have found my answer as you have predicted, thank you so much kind sir, It was simply a typing error.

    • one year ago
  29. geoffb Group Title
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    http://www.wolframalpha.com/input/?i=sin%5E-1%280.882%29

    • one year ago
  30. geoffb Group Title
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    Good stuff! You're very welcome. :)

    • one year ago
  31. kennedav000 Group Title
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    I shall be on my way! Good day to you, and thank you for your time.

    • one year ago
  32. geoffb Group Title
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    You too, David! Cheers!

    • one year ago
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