anonymous
  • anonymous
HELP! calculate the lenght of the curve: x^(2/3)+y^(2/3)=9 thanks
MIT 18.02 Multivariable Calculus, Fall 2007
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
71 units...i guess..
anonymous
  • anonymous
Well you need to get the limits first. Are they given? Get your equation into the form y=f(x) then apply the equation \[S= \int\limits_{a}^{b} \sqrt{(1+(dy/dx)^2) } dx\]
kyosuke
  • kyosuke
Mira, te recomiendo parametrizar tu ecuaciĆ³n de esta forma: x=27cos^3 (t) y=27sin^3(t) si los reemplazas uno con otro obtienes lo mismo ( x ^ (2/3) + y ^ (2/3) = 9) luego aplicas la integral para calcular la longitud \[4*\int\limits_{0}^{\pi/2} \sqrt {(27cos^{3} t)\prime^2+(27sen ^{3}t )\prime^2} dt\] si integras eso te debe salir 162 suerte.

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