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HELP!
calculate the lenght of the curve:
x^(2/3)+y^(2/3)=9
thanks
 one year ago
 one year ago
HELP! calculate the lenght of the curve: x^(2/3)+y^(2/3)=9 thanks
 one year ago
 one year ago

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sankaran.sreeBest ResponseYou've already chosen the best response.1
71 units...i guess..
 one year ago

ArcturasBest ResponseYou've already chosen the best response.1
Well you need to get the limits first. Are they given? Get your equation into the form y=f(x) then apply the equation \[S= \int\limits_{a}^{b} \sqrt{(1+(dy/dx)^2) } dx\]
 one year ago

kyosukeBest ResponseYou've already chosen the best response.0
Mira, te recomiendo parametrizar tu ecuación de esta forma: x=27cos^3 (t) y=27sin^3(t) si los reemplazas uno con otro obtienes lo mismo ( x ^ (2/3) + y ^ (2/3) = 9) luego aplicas la integral para calcular la longitud \[4*\int\limits_{0}^{\pi/2} \sqrt {(27cos^{3} t)\prime^2+(27sen ^{3}t )\prime^2} dt\] si integras eso te debe salir 162 suerte.
 one year ago
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