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Andreslvc

HELP! calculate the lenght of the curve: x^(2/3)+y^(2/3)=9 thanks

  • one year ago
  • one year ago

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  1. sankaran.sree
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    71 units...i guess..

    • one year ago
  2. Arcturas
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    Well you need to get the limits first. Are they given? Get your equation into the form y=f(x) then apply the equation \[S= \int\limits_{a}^{b} \sqrt{(1+(dy/dx)^2) } dx\]

    • one year ago
  3. kyosuke
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    Mira, te recomiendo parametrizar tu ecuación de esta forma: x=27cos^3 (t) y=27sin^3(t) si los reemplazas uno con otro obtienes lo mismo ( x ^ (2/3) + y ^ (2/3) = 9) luego aplicas la integral para calcular la longitud \[4*\int\limits_{0}^{\pi/2} \sqrt {(27cos^{3} t)\prime^2+(27sen ^{3}t )\prime^2} dt\] si integras eso te debe salir 162 suerte.

    • one year ago
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