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InsanelyChaotic
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Please help me? :)
Rationalize the denominator of √49/(72i)  (4+9i)
My answer: 49+21i/58
 2 years ago
 2 years ago
InsanelyChaotic Group Title
Please help me? :) Rationalize the denominator of √49/(72i)  (4+9i) My answer: 49+21i/58
 2 years ago
 2 years ago

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RajshikharGupta Group TitleBest ResponseYou've already chosen the best response.0
plz put brackets after each expression so that ur ques get clear to me
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
ok koala ;0
 2 years ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.1
√49/(72i)  (4+9i) is this like this? \[\sqrt{(\frac{ 49 }{ 72i })}(4+9i)?\]
 2 years ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.1
or is it like this? \[\sqrt{\frac{ 49 }{ 72i }(4+9i)}?\]
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
yes!!! :))
 2 years ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.1
or is it like this? \[\sqrt{\frac{ 49 }{(72i)(4+9i) }}\]?
 2 years ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.1
which one now? the first, second or the third?
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
the former was correct ;)
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
the first one :)
 2 years ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.1
ok the first one is \[\sqrt{\frac{ 49 }{ 72i }( \frac{ 7+2i }{ 7+2i })}(4+9i)\] \[\sqrt{\frac{ 49(7+2i) }{ 494i ^{2} }}(4+9i)\] \[\sqrt{\frac{ 49(7+2i) }{ 494(1) }}(4+9i)\] can you further simplify them ?
 2 years ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.1
= sqrt[(34398i)/53](4+9i) =sqrt[6.4721.85i](4+9i)
 2 years ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.1
ok i think we cant simplify them any more :D
 2 years ago

InsanelyChaotic Group TitleBest ResponseYou've already chosen the best response.0
thank you kind sir!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!11111
 2 years ago

mark_o. Group TitleBest ResponseYou've already chosen the best response.1
ok YW have fun now and good luck ... :D
 2 years ago
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