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Hahaha I know how to use wolframalpha! I don't how to get there :P

Use Euler's formula. You know it?

No, I'll look into it though and post back.

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\[\Im((e^{i\theta})^5)=\Im(e^{i5\theta})\]

\[\sqrt{-1}=i=\text{ imaginary number } \]
My method may look tricky, but it's MUCH simpler

http://betterexplained.com/articles/a-visual-intuitive-guide-to-imaginary-numbers/

*of

Blufoot, you're on the right track, use sin(a+b)=sinacosb+sinbcosa

wait is this
\[\sin ^{5}x\]
or
\[\sin(5x)\]

I'm afraid you are :(

I am sorry but I actually have got to go bye

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