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kerribaberri

  • 3 years ago

when kx3 + px2 - x + 3 is divided by x - 1, the remainder is 4. When kx3 + px2 is divided by x - 2, the remainder is 21. Find the values of k and p.

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  1. hba
    • 3 years ago
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    |dw:1353959611123:dw| got this part ?

  2. hba
    • 3 years ago
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    Lets do this fast @kerribaberri Just tell me if you do not understand.

  3. kerribaberri
    • 3 years ago
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    yeah!

  4. kerribaberri
    • 3 years ago
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    alright, is there another way to do this though rather than to divide all the time?

  5. kerribaberri
    • 3 years ago
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    an easier solution or something?

  6. hba
    • 3 years ago
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    @kerribaberri This is the easiest method on earth if you learn it The easiest and the fastest :)

  7. kerribaberri
    • 3 years ago
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    alright! let's do this LOL

  8. hba
    • 3 years ago
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    |dw:1353959860849:dw| We take the k down.

  9. hba
    • 3 years ago
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    |dw:1353959905760:dw| We multiply the k by 1 k*1=k

  10. hba
    • 3 years ago
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    |dw:1353959933565:dw| We multiply it and put it there,following me @kerribaberri

  11. kerribaberri
    • 3 years ago
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    okay so we multiply everything by the 1, yes?

  12. hba
    • 3 years ago
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    Yeah

  13. kerribaberri
    • 3 years ago
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    why is it just 1 rather than x - 1?

  14. hba
    • 3 years ago
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    |dw:1353960062608:dw| We add p and q so we get p+q now and then multiply it by 1

  15. hba
    • 3 years ago
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    In this method we take x-1 put it equal to 0 so x-1=0 x=1 So we have to put this .

  16. hba
    • 3 years ago
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    Did you get my step above shown in the diag ?

  17. kerribaberri
    • 3 years ago
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    yes, i did.

  18. kerribaberri
    • 3 years ago
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    is it usually the opposite? so instead of -1 it is 1?

  19. kerribaberri
    • 3 years ago
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    so if i was to be given x - 3, it would be divided all by 3?

  20. hba
    • 3 years ago
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    |dw:1353960245291:dw| here we have added (p+q)+(-1)=p+q-1 and then multiply it by 1

  21. hba
    • 3 years ago
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    @kerribaberri Yeah you are right but if the question come 2x-2=0 then 2x=2 x=1

  22. hba
    • 3 years ago
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    Did you get my step above ?

  23. kerribaberri
    • 3 years ago
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    ahh, i see okay

  24. kerribaberri
    • 3 years ago
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    then the last step after that would be (p + k - 1 + 3) ?

  25. hba
    • 3 years ago
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    |dw:1353960431384:dw| Yeah right :D Shall i continue ?

  26. kerribaberri
    • 3 years ago
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    :D sure

  27. hba
    • 3 years ago
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    |dw:1353960534857:dw| We will always seprate the last number :)

  28. hba
    • 3 years ago
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    I know you will ask why ? right ?

  29. hba
    • 3 years ago
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    @kerribaberri ?

  30. kerribaberri
    • 3 years ago
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    yeah, why? :P

  31. kerribaberri
    • 3 years ago
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    i was wondering why there was a line in between

  32. hba
    • 3 years ago
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    |dw:1353960695933:dw| Here P(x)=polynomial of x and R(x)=remainder of x So we seprate them ,Got it @kerribaberri ?

  33. kerribaberri
    • 3 years ago
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    ohhh okay i get it @hba

  34. hba
    • 3 years ago
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    We have been provided in the question that the remainder is 4 so R(x)=4 got it ?

  35. hba
    • 3 years ago
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    @kerribaberri ??

  36. kerribaberri
    • 3 years ago
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    yup :)

  37. kerribaberri
    • 3 years ago
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    yeah, i got it. :)

  38. hba
    • 3 years ago
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    I can replace R(x) with p+k-1+3 so p+k+2=4 got it @kerribaberri ?

  39. kerribaberri
    • 3 years ago
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    yes @hba

  40. hba
    • 3 years ago
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    so p+k=4-2 p+k=2

  41. hba
    • 3 years ago
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    Now lets solve the other one.|dw:1353961284346:dw| Your turn @kerribaberri Do it i'll help you where you go wrong :)

  42. kerribaberri
    • 3 years ago
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    so 2 goes on the left..

  43. hba
    • 3 years ago
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    Yeah start doing it in the diag

  44. kerribaberri
    • 3 years ago
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    k p -2 2 ? o_O

  45. hba
    • 3 years ago
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    Do it in the diag lol

  46. hba
    • 3 years ago
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    Do you see a pencil on my diag press it and start working

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  47. kerribaberri
    • 3 years ago
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    okayy

  48. kerribaberri
    • 3 years ago
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    LOL did i pick the correct numbers though?

  49. kerribaberri
    • 3 years ago
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    |dw:1353961667693:dw|

  50. hba
    • 3 years ago
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    Where did -2 and +2 come from ?

  51. kerribaberri
    • 3 years ago
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    |dw:1353961803438:dw|

  52. kerribaberri
    • 3 years ago
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    i took the 2 from the equation and.. ohhhhhhh am i supposed to multiply -2 by 3?

  53. kerribaberri
    • 3 years ago
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    ohhhh wait, i didn't realize the 3 and the 2 were exponents..

  54. kerribaberri
    • 3 years ago
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    i thought they were base numbers

  55. hba
    • 3 years ago
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    The equation in the first thing was kx3 + px2 - x + 3 so i got k p -1 3 In the second case the equation iss kx^3+px^2 so you should get k p right ?

  56. hba
    • 3 years ago
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    |dw:1353962035949:dw||dw:1353962058098:dw|

  57. hba
    • 3 years ago
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    Got it ?

  58. hba
    • 3 years ago
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    @kerribaberri Please concentrate Its easy.

  59. kerribaberri
    • 3 years ago
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    okay i got it..

  60. kerribaberri
    • 3 years ago
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    i see where the k and p are coming from but i don't see where the last two come from

  61. hba
    • 3 years ago
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    |dw:1353962174399:dw| Now continue

  62. hba
    • 3 years ago
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    |dw:1353962211804:dw|

  63. hba
    • 3 years ago
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    Got where the last two came from ?

  64. kerribaberri
    • 3 years ago
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    yeah i see it there because there are numbers, but this one has none?

  65. hba
    • 3 years ago
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    So you do not have to write anything.

  66. hba
    • 3 years ago
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    |dw:1353962420562:dw|

  67. kerribaberri
    • 3 years ago
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    ohhh, i never thought that was an option

  68. hba
    • 3 years ago
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    Are you solving it now lol ?

  69. kerribaberri
    • 3 years ago
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    r(x) = 21

  70. hba
    • 3 years ago
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    @kerribaberri Please try.

  71. hba
    • 3 years ago
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    @kerribaberri First solve it lol

  72. hba
    • 3 years ago
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    |dw:1353962559852:dw| bring the k down multiply it by 2

  73. kerribaberri
    • 3 years ago
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    if there's no numbers|dw:1353962609644:dw|

  74. hba
    • 3 years ago
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    What is wrong with you ?

  75. hba
    • 3 years ago
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    The method is bring the k down multiply i by 2 so it will become 2k then it will go under p

  76. hba
    • 3 years ago
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    @kerribaberri Please try to understand i feel like slamming my head in the wall.

  77. hba
    • 3 years ago
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    @kerribaberri You there ?

  78. kerribaberri
    • 3 years ago
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    i'll just ask someone else LOL

  79. hba
    • 3 years ago
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    No i am showing you wait.

  80. kerribaberri
    • 3 years ago
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    No you are not..

  81. hba
    • 3 years ago
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    |dw:1353963033373:dw|

  82. hba
    • 3 years ago
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    So, R(x)=21 2x+p=21 got it ?

  83. hba
    • 3 years ago
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    |dw:1353963147883:dw|

  84. hba
    • 3 years ago
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    |dw:1353963244019:dw|

  85. hba
    • 3 years ago
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    @kerribaberri got it ?

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