Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

kerribaberri

  • 2 years ago

when kx3 + px2 - x + 3 is divided by x - 1, the remainder is 4. When kx3 + px2 is divided by x - 2, the remainder is 21. Find the values of k and p.

  • This Question is Open
  1. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1353959611123:dw| got this part ?

  2. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Lets do this fast @kerribaberri Just tell me if you do not understand.

  3. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah!

  4. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    alright, is there another way to do this though rather than to divide all the time?

  5. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    an easier solution or something?

  6. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @kerribaberri This is the easiest method on earth if you learn it The easiest and the fastest :)

  7. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    alright! let's do this LOL

  8. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1353959860849:dw| We take the k down.

  9. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1353959905760:dw| We multiply the k by 1 k*1=k

  10. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1353959933565:dw| We multiply it and put it there,following me @kerribaberri

  11. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay so we multiply everything by the 1, yes?

  12. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Yeah

  13. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    why is it just 1 rather than x - 1?

  14. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1353960062608:dw| We add p and q so we get p+q now and then multiply it by 1

  15. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    In this method we take x-1 put it equal to 0 so x-1=0 x=1 So we have to put this .

  16. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Did you get my step above shown in the diag ?

  17. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes, i did.

  18. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    is it usually the opposite? so instead of -1 it is 1?

  19. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so if i was to be given x - 3, it would be divided all by 3?

  20. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1353960245291:dw| here we have added (p+q)+(-1)=p+q-1 and then multiply it by 1

  21. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @kerribaberri Yeah you are right but if the question come 2x-2=0 then 2x=2 x=1

  22. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Did you get my step above ?

  23. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ahh, i see okay

  24. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then the last step after that would be (p + k - 1 + 3) ?

  25. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1353960431384:dw| Yeah right :D Shall i continue ?

  26. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    :D sure

  27. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1353960534857:dw| We will always seprate the last number :)

  28. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I know you will ask why ? right ?

  29. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @kerribaberri ?

  30. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah, why? :P

  31. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i was wondering why there was a line in between

  32. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1353960695933:dw| Here P(x)=polynomial of x and R(x)=remainder of x So we seprate them ,Got it @kerribaberri ?

  33. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ohhh okay i get it @hba

  34. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    We have been provided in the question that the remainder is 4 so R(x)=4 got it ?

  35. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @kerribaberri ??

  36. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yup :)

  37. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah, i got it. :)

  38. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I can replace R(x) with p+k-1+3 so p+k+2=4 got it @kerribaberri ?

  39. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes @hba

  40. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so p+k=4-2 p+k=2

  41. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Now lets solve the other one.|dw:1353961284346:dw| Your turn @kerribaberri Do it i'll help you where you go wrong :)

  42. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so 2 goes on the left..

  43. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Yeah start doing it in the diag

  44. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    k p -2 2 ? o_O

  45. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Do it in the diag lol

  46. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Do you see a pencil on my diag press it and start working

    1 Attachment
  47. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okayy

  48. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    LOL did i pick the correct numbers though?

  49. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1353961667693:dw|

  50. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Where did -2 and +2 come from ?

  51. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1353961803438:dw|

  52. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i took the 2 from the equation and.. ohhhhhhh am i supposed to multiply -2 by 3?

  53. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ohhhh wait, i didn't realize the 3 and the 2 were exponents..

  54. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i thought they were base numbers

  55. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    The equation in the first thing was kx3 + px2 - x + 3 so i got k p -1 3 In the second case the equation iss kx^3+px^2 so you should get k p right ?

  56. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1353962035949:dw||dw:1353962058098:dw|

  57. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Got it ?

  58. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @kerribaberri Please concentrate Its easy.

  59. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay i got it..

  60. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i see where the k and p are coming from but i don't see where the last two come from

  61. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1353962174399:dw| Now continue

  62. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1353962211804:dw|

  63. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Got where the last two came from ?

  64. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah i see it there because there are numbers, but this one has none?

  65. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    So you do not have to write anything.

  66. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1353962420562:dw|

  67. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ohhh, i never thought that was an option

  68. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Are you solving it now lol ?

  69. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    r(x) = 21

  70. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @kerribaberri Please try.

  71. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @kerribaberri First solve it lol

  72. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1353962559852:dw| bring the k down multiply it by 2

  73. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    if there's no numbers|dw:1353962609644:dw|

  74. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    What is wrong with you ?

  75. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    The method is bring the k down multiply i by 2 so it will become 2k then it will go under p

  76. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @kerribaberri Please try to understand i feel like slamming my head in the wall.

  77. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @kerribaberri You there ?

  78. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i'll just ask someone else LOL

  79. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    No i am showing you wait.

  80. kerribaberri
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No you are not..

  81. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1353963033373:dw|

  82. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    So, R(x)=21 2x+p=21 got it ?

  83. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1353963147883:dw|

  84. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1353963244019:dw|

  85. hba
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @kerribaberri got it ?

  86. Not the answer you are looking for?
    Search for more explanations.

    Search OpenStudy
    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.