anonymous
  • anonymous
when kx3 + px2 - x + 3 is divided by x - 1, the remainder is 4. When kx3 + px2 is divided by x - 2, the remainder is 21. Find the values of k and p.
Mathematics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

hba
  • hba
|dw:1353959611123:dw| got this part ?
hba
  • hba
Lets do this fast @kerribaberri Just tell me if you do not understand.
anonymous
  • anonymous
yeah!

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
alright, is there another way to do this though rather than to divide all the time?
anonymous
  • anonymous
an easier solution or something?
hba
  • hba
@kerribaberri This is the easiest method on earth if you learn it The easiest and the fastest :)
anonymous
  • anonymous
alright! let's do this LOL
hba
  • hba
|dw:1353959860849:dw| We take the k down.
hba
  • hba
|dw:1353959905760:dw| We multiply the k by 1 k*1=k
hba
  • hba
|dw:1353959933565:dw| We multiply it and put it there,following me @kerribaberri
anonymous
  • anonymous
okay so we multiply everything by the 1, yes?
hba
  • hba
Yeah
anonymous
  • anonymous
why is it just 1 rather than x - 1?
hba
  • hba
|dw:1353960062608:dw| We add p and q so we get p+q now and then multiply it by 1
hba
  • hba
In this method we take x-1 put it equal to 0 so x-1=0 x=1 So we have to put this .
hba
  • hba
Did you get my step above shown in the diag ?
anonymous
  • anonymous
yes, i did.
anonymous
  • anonymous
is it usually the opposite? so instead of -1 it is 1?
anonymous
  • anonymous
so if i was to be given x - 3, it would be divided all by 3?
hba
  • hba
|dw:1353960245291:dw| here we have added (p+q)+(-1)=p+q-1 and then multiply it by 1
hba
  • hba
@kerribaberri Yeah you are right but if the question come 2x-2=0 then 2x=2 x=1
hba
  • hba
Did you get my step above ?
anonymous
  • anonymous
ahh, i see okay
anonymous
  • anonymous
then the last step after that would be (p + k - 1 + 3) ?
hba
  • hba
|dw:1353960431384:dw| Yeah right :D Shall i continue ?
anonymous
  • anonymous
:D sure
hba
  • hba
|dw:1353960534857:dw| We will always seprate the last number :)
hba
  • hba
I know you will ask why ? right ?
hba
  • hba
@kerribaberri ?
anonymous
  • anonymous
yeah, why? :P
anonymous
  • anonymous
i was wondering why there was a line in between
hba
  • hba
|dw:1353960695933:dw| Here P(x)=polynomial of x and R(x)=remainder of x So we seprate them ,Got it @kerribaberri ?
anonymous
  • anonymous
ohhh okay i get it @hba
hba
  • hba
We have been provided in the question that the remainder is 4 so R(x)=4 got it ?
hba
  • hba
@kerribaberri ??
anonymous
  • anonymous
yup :)
anonymous
  • anonymous
yeah, i got it. :)
hba
  • hba
I can replace R(x) with p+k-1+3 so p+k+2=4 got it @kerribaberri ?
anonymous
  • anonymous
yes @hba
hba
  • hba
so p+k=4-2 p+k=2
hba
  • hba
Now lets solve the other one.|dw:1353961284346:dw| Your turn @kerribaberri Do it i'll help you where you go wrong :)
anonymous
  • anonymous
so 2 goes on the left..
hba
  • hba
Yeah start doing it in the diag
anonymous
  • anonymous
k p -2 2 ? o_O
hba
  • hba
Do it in the diag lol
hba
  • hba
Do you see a pencil on my diag press it and start working
1 Attachment
anonymous
  • anonymous
okayy
anonymous
  • anonymous
LOL did i pick the correct numbers though?
anonymous
  • anonymous
|dw:1353961667693:dw|
hba
  • hba
Where did -2 and +2 come from ?
anonymous
  • anonymous
|dw:1353961803438:dw|
anonymous
  • anonymous
i took the 2 from the equation and.. ohhhhhhh am i supposed to multiply -2 by 3?
anonymous
  • anonymous
ohhhh wait, i didn't realize the 3 and the 2 were exponents..
anonymous
  • anonymous
i thought they were base numbers
hba
  • hba
The equation in the first thing was kx3 + px2 - x + 3 so i got k p -1 3 In the second case the equation iss kx^3+px^2 so you should get k p right ?
hba
  • hba
|dw:1353962035949:dw||dw:1353962058098:dw|
hba
  • hba
Got it ?
hba
  • hba
@kerribaberri Please concentrate Its easy.
anonymous
  • anonymous
okay i got it..
anonymous
  • anonymous
i see where the k and p are coming from but i don't see where the last two come from
hba
  • hba
|dw:1353962174399:dw| Now continue
hba
  • hba
|dw:1353962211804:dw|
hba
  • hba
Got where the last two came from ?
anonymous
  • anonymous
yeah i see it there because there are numbers, but this one has none?
hba
  • hba
So you do not have to write anything.
hba
  • hba
|dw:1353962420562:dw|
anonymous
  • anonymous
ohhh, i never thought that was an option
hba
  • hba
Are you solving it now lol ?
anonymous
  • anonymous
r(x) = 21
hba
  • hba
@kerribaberri Please try.
hba
  • hba
@kerribaberri First solve it lol
hba
  • hba
|dw:1353962559852:dw| bring the k down multiply it by 2
anonymous
  • anonymous
if there's no numbers|dw:1353962609644:dw|
hba
  • hba
What is wrong with you ?
hba
  • hba
The method is bring the k down multiply i by 2 so it will become 2k then it will go under p
hba
  • hba
@kerribaberri Please try to understand i feel like slamming my head in the wall.
hba
  • hba
@kerribaberri You there ?
anonymous
  • anonymous
i'll just ask someone else LOL
hba
  • hba
No i am showing you wait.
anonymous
  • anonymous
No you are not..
hba
  • hba
|dw:1353963033373:dw|
hba
  • hba
So, R(x)=21 2x+p=21 got it ?
hba
  • hba
|dw:1353963147883:dw|
hba
  • hba
|dw:1353963244019:dw|
hba
  • hba
@kerribaberri got it ?

Looking for something else?

Not the answer you are looking for? Search for more explanations.