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when kx3 + px2  x + 3 is divided by x  1, the remainder is 4. When kx3 + px2 is divided by x  2, the remainder is 21. Find the values of k and p.
 one year ago
 one year ago
when kx3 + px2  x + 3 is divided by x  1, the remainder is 4. When kx3 + px2 is divided by x  2, the remainder is 21. Find the values of k and p.
 one year ago
 one year ago

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hbaBest ResponseYou've already chosen the best response.1
dw:1353959611123:dw got this part ?
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Lets do this fast @kerribaberri Just tell me if you do not understand.
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
alright, is there another way to do this though rather than to divide all the time?
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
an easier solution or something?
 one year ago

hbaBest ResponseYou've already chosen the best response.1
@kerribaberri This is the easiest method on earth if you learn it The easiest and the fastest :)
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
alright! let's do this LOL
 one year ago

hbaBest ResponseYou've already chosen the best response.1
dw:1353959860849:dw We take the k down.
 one year ago

hbaBest ResponseYou've already chosen the best response.1
dw:1353959905760:dw We multiply the k by 1 k*1=k
 one year ago

hbaBest ResponseYou've already chosen the best response.1
dw:1353959933565:dw We multiply it and put it there,following me @kerribaberri
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
okay so we multiply everything by the 1, yes?
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
why is it just 1 rather than x  1?
 one year ago

hbaBest ResponseYou've already chosen the best response.1
dw:1353960062608:dw We add p and q so we get p+q now and then multiply it by 1
 one year ago

hbaBest ResponseYou've already chosen the best response.1
In this method we take x1 put it equal to 0 so x1=0 x=1 So we have to put this .
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Did you get my step above shown in the diag ?
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
is it usually the opposite? so instead of 1 it is 1?
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
so if i was to be given x  3, it would be divided all by 3?
 one year ago

hbaBest ResponseYou've already chosen the best response.1
dw:1353960245291:dw here we have added (p+q)+(1)=p+q1 and then multiply it by 1
 one year ago

hbaBest ResponseYou've already chosen the best response.1
@kerribaberri Yeah you are right but if the question come 2x2=0 then 2x=2 x=1
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Did you get my step above ?
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
then the last step after that would be (p + k  1 + 3) ?
 one year ago

hbaBest ResponseYou've already chosen the best response.1
dw:1353960431384:dw Yeah right :D Shall i continue ?
 one year ago

hbaBest ResponseYou've already chosen the best response.1
dw:1353960534857:dw We will always seprate the last number :)
 one year ago

hbaBest ResponseYou've already chosen the best response.1
I know you will ask why ? right ?
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
i was wondering why there was a line in between
 one year ago

hbaBest ResponseYou've already chosen the best response.1
dw:1353960695933:dw Here P(x)=polynomial of x and R(x)=remainder of x So we seprate them ,Got it @kerribaberri ?
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
ohhh okay i get it @hba
 one year ago

hbaBest ResponseYou've already chosen the best response.1
We have been provided in the question that the remainder is 4 so R(x)=4 got it ?
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
yeah, i got it. :)
 one year ago

hbaBest ResponseYou've already chosen the best response.1
I can replace R(x) with p+k1+3 so p+k+2=4 got it @kerribaberri ?
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Now lets solve the other one.dw:1353961284346:dw Your turn @kerribaberri Do it i'll help you where you go wrong :)
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
so 2 goes on the left..
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Yeah start doing it in the diag
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Do you see a pencil on my diag press it and start working
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
LOL did i pick the correct numbers though?
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
dw:1353961667693:dw
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Where did 2 and +2 come from ?
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
dw:1353961803438:dw
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
i took the 2 from the equation and.. ohhhhhhh am i supposed to multiply 2 by 3?
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
ohhhh wait, i didn't realize the 3 and the 2 were exponents..
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
i thought they were base numbers
 one year ago

hbaBest ResponseYou've already chosen the best response.1
The equation in the first thing was kx3 + px2  x + 3 so i got k p 1 3 In the second case the equation iss kx^3+px^2 so you should get k p right ?
 one year ago

hbaBest ResponseYou've already chosen the best response.1
dw:1353962035949:dwdw:1353962058098:dw
 one year ago

hbaBest ResponseYou've already chosen the best response.1
@kerribaberri Please concentrate Its easy.
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
i see where the k and p are coming from but i don't see where the last two come from
 one year ago

hbaBest ResponseYou've already chosen the best response.1
dw:1353962174399:dw Now continue
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Got where the last two came from ?
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
yeah i see it there because there are numbers, but this one has none?
 one year ago

hbaBest ResponseYou've already chosen the best response.1
So you do not have to write anything.
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
ohhh, i never thought that was an option
 one year ago

hbaBest ResponseYou've already chosen the best response.1
Are you solving it now lol ?
 one year ago

hbaBest ResponseYou've already chosen the best response.1
@kerribaberri First solve it lol
 one year ago

hbaBest ResponseYou've already chosen the best response.1
dw:1353962559852:dw bring the k down multiply it by 2
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
if there's no numbersdw:1353962609644:dw
 one year ago

hbaBest ResponseYou've already chosen the best response.1
The method is bring the k down multiply i by 2 so it will become 2k then it will go under p
 one year ago

hbaBest ResponseYou've already chosen the best response.1
@kerribaberri Please try to understand i feel like slamming my head in the wall.
 one year ago

kerribaberriBest ResponseYou've already chosen the best response.0
i'll just ask someone else LOL
 one year ago

hbaBest ResponseYou've already chosen the best response.1
So, R(x)=21 2x+p=21 got it ?
 one year ago
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