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|dw:1353959611123:dw|
got this part ?

Lets do this fast @kerribaberri Just tell me if you do not understand.

yeah!

alright, is there another way to do this though rather than to divide all the time?

an easier solution or something?

@kerribaberri This is the easiest method on earth if you learn it
The easiest and the fastest :)

alright! let's do this LOL

|dw:1353959860849:dw|
We take the k down.

|dw:1353959905760:dw|
We multiply the k by 1 k*1=k

|dw:1353959933565:dw|
We multiply it and put it there,following me @kerribaberri

okay so we multiply everything by the 1, yes?

Yeah

why is it just 1 rather than x - 1?

|dw:1353960062608:dw|
We add p and q so we get p+q now and then multiply it by 1

In this method we take x-1 put it equal to 0
so
x-1=0
x=1
So we have to put this .

Did you get my step above shown in the diag ?

yes, i did.

is it usually the opposite? so instead of -1 it is 1?

so if i was to be given x - 3, it would be divided all by 3?

|dw:1353960245291:dw|
here we have added (p+q)+(-1)=p+q-1 and then multiply it by 1

@kerribaberri Yeah you are right but if the question come 2x-2=0 then
2x=2
x=1

Did you get my step above ?

ahh, i see okay

then the last step after that would be (p + k - 1 + 3) ?

|dw:1353960431384:dw|
Yeah right :D
Shall i continue ?

:D sure

|dw:1353960534857:dw|
We will always seprate the last number :)

I know you will ask why ? right ?

yeah, why? :P

i was wondering why there was a line in between

We have been provided in the question that the remainder is 4
so
R(x)=4
got it ?

yup :)

yeah, i got it. :)

I can replace R(x) with p+k-1+3
so
p+k+2=4
got it @kerribaberri ?

so p+k=4-2
p+k=2

so 2 goes on the left..

Yeah start doing it in the diag

k p -2 2 ? o_O

Do it in the diag lol

Do you see a pencil on my diag press it and start working

okayy

LOL did i pick the correct numbers though?

|dw:1353961667693:dw|

Where did -2 and +2 come from ?

|dw:1353961803438:dw|

i took the 2 from the equation and.. ohhhhhhh am i supposed to multiply -2 by 3?

ohhhh wait, i didn't realize the 3 and the 2 were exponents..

i thought they were base numbers

|dw:1353962035949:dw||dw:1353962058098:dw|

Got it ?

@kerribaberri Please concentrate Its easy.

okay i got it..

i see where the k and p are coming from but i don't see where the last two come from

|dw:1353962174399:dw|
Now continue

|dw:1353962211804:dw|

Got where the last two came from ?

yeah i see it there because there are numbers, but this one has none?

So you do not have to write anything.

|dw:1353962420562:dw|

ohhh, i never thought that was an option

Are you solving it now lol ?

r(x) = 21

@kerribaberri Please try.

@kerribaberri First solve it lol

|dw:1353962559852:dw|
bring the k down multiply it by 2

if there's no numbers|dw:1353962609644:dw|

What is wrong with you ?

The method is bring the k down multiply i by 2 so it will become 2k then it will go under p

@kerribaberri Please try to understand i feel like slamming my head in the wall.

@kerribaberri You there ?

i'll just ask someone else LOL

No i am showing you wait.

No you are not..

|dw:1353963033373:dw|

So,
R(x)=21
2x+p=21
got it ?

|dw:1353963147883:dw|

|dw:1353963244019:dw|

@kerribaberri got it ?