A community for students.
Here's the question you clicked on:
 0 viewing
kerribaberri
 2 years ago
when kx3 + px2  x + 3 is divided by x  1, the remainder is 4. When kx3 + px2 is divided by x  2, the remainder is 21. Find the values of k and p.
kerribaberri
 2 years ago
when kx3 + px2  x + 3 is divided by x  1, the remainder is 4. When kx3 + px2 is divided by x  2, the remainder is 21. Find the values of k and p.

This Question is Open

hba
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1353959611123:dw got this part ?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Lets do this fast @kerribaberri Just tell me if you do not understand.

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0alright, is there another way to do this though rather than to divide all the time?

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0an easier solution or something?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1@kerribaberri This is the easiest method on earth if you learn it The easiest and the fastest :)

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0alright! let's do this LOL

hba
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1353959860849:dw We take the k down.

hba
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1353959905760:dw We multiply the k by 1 k*1=k

hba
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1353959933565:dw We multiply it and put it there,following me @kerribaberri

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0okay so we multiply everything by the 1, yes?

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0why is it just 1 rather than x  1?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1353960062608:dw We add p and q so we get p+q now and then multiply it by 1

hba
 2 years ago
Best ResponseYou've already chosen the best response.1In this method we take x1 put it equal to 0 so x1=0 x=1 So we have to put this .

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Did you get my step above shown in the diag ?

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0is it usually the opposite? so instead of 1 it is 1?

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0so if i was to be given x  3, it would be divided all by 3?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1353960245291:dw here we have added (p+q)+(1)=p+q1 and then multiply it by 1

hba
 2 years ago
Best ResponseYou've already chosen the best response.1@kerribaberri Yeah you are right but if the question come 2x2=0 then 2x=2 x=1

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Did you get my step above ?

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0then the last step after that would be (p + k  1 + 3) ?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1353960431384:dw Yeah right :D Shall i continue ?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1353960534857:dw We will always seprate the last number :)

hba
 2 years ago
Best ResponseYou've already chosen the best response.1I know you will ask why ? right ?

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0i was wondering why there was a line in between

hba
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1353960695933:dw Here P(x)=polynomial of x and R(x)=remainder of x So we seprate them ,Got it @kerribaberri ?

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0ohhh okay i get it @hba

hba
 2 years ago
Best ResponseYou've already chosen the best response.1We have been provided in the question that the remainder is 4 so R(x)=4 got it ?

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0yeah, i got it. :)

hba
 2 years ago
Best ResponseYou've already chosen the best response.1I can replace R(x) with p+k1+3 so p+k+2=4 got it @kerribaberri ?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Now lets solve the other one.dw:1353961284346:dw Your turn @kerribaberri Do it i'll help you where you go wrong :)

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0so 2 goes on the left..

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Yeah start doing it in the diag

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Do you see a pencil on my diag press it and start working

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0LOL did i pick the correct numbers though?

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1353961667693:dw

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Where did 2 and +2 come from ?

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1353961803438:dw

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0i took the 2 from the equation and.. ohhhhhhh am i supposed to multiply 2 by 3?

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0ohhhh wait, i didn't realize the 3 and the 2 were exponents..

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0i thought they were base numbers

hba
 2 years ago
Best ResponseYou've already chosen the best response.1The equation in the first thing was kx3 + px2  x + 3 so i got k p 1 3 In the second case the equation iss kx^3+px^2 so you should get k p right ?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1353962035949:dwdw:1353962058098:dw

hba
 2 years ago
Best ResponseYou've already chosen the best response.1@kerribaberri Please concentrate Its easy.

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0i see where the k and p are coming from but i don't see where the last two come from

hba
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1353962174399:dw Now continue

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Got where the last two came from ?

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0yeah i see it there because there are numbers, but this one has none?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1So you do not have to write anything.

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0ohhh, i never thought that was an option

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Are you solving it now lol ?

hba
 2 years ago
Best ResponseYou've already chosen the best response.1@kerribaberri First solve it lol

hba
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1353962559852:dw bring the k down multiply it by 2

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0if there's no numbersdw:1353962609644:dw

hba
 2 years ago
Best ResponseYou've already chosen the best response.1The method is bring the k down multiply i by 2 so it will become 2k then it will go under p

hba
 2 years ago
Best ResponseYou've already chosen the best response.1@kerribaberri Please try to understand i feel like slamming my head in the wall.

kerribaberri
 2 years ago
Best ResponseYou've already chosen the best response.0i'll just ask someone else LOL

hba
 2 years ago
Best ResponseYou've already chosen the best response.1So, R(x)=21 2x+p=21 got it ?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.