kerribaberri
when kx3 + px2  x + 3 is divided by x  1, the remainder is 4. When kx3 + px2 is divided by x  2, the remainder is 21. Find the values of k and p.



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hba
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dw:1353959611123:dw
got this part ?

hba
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Lets do this fast @kerribaberri Just tell me if you do not understand.

kerribaberri
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yeah!

kerribaberri
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alright, is there another way to do this though rather than to divide all the time?

kerribaberri
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an easier solution or something?

hba
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@kerribaberri This is the easiest method on earth if you learn it
The easiest and the fastest :)

kerribaberri
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alright! let's do this LOL

hba
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dw:1353959860849:dw
We take the k down.

hba
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dw:1353959905760:dw
We multiply the k by 1 k*1=k

hba
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dw:1353959933565:dw
We multiply it and put it there,following me @kerribaberri

kerribaberri
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okay so we multiply everything by the 1, yes?

hba
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Yeah

kerribaberri
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why is it just 1 rather than x  1?

hba
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dw:1353960062608:dw
We add p and q so we get p+q now and then multiply it by 1

hba
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In this method we take x1 put it equal to 0
so
x1=0
x=1
So we have to put this .

hba
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Did you get my step above shown in the diag ?

kerribaberri
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yes, i did.

kerribaberri
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is it usually the opposite? so instead of 1 it is 1?

kerribaberri
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so if i was to be given x  3, it would be divided all by 3?

hba
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dw:1353960245291:dw
here we have added (p+q)+(1)=p+q1 and then multiply it by 1

hba
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@kerribaberri Yeah you are right but if the question come 2x2=0 then
2x=2
x=1

hba
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Did you get my step above ?

kerribaberri
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ahh, i see okay

kerribaberri
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then the last step after that would be (p + k  1 + 3) ?

hba
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dw:1353960431384:dw
Yeah right :D
Shall i continue ?

kerribaberri
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:D sure

hba
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dw:1353960534857:dw
We will always seprate the last number :)

hba
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I know you will ask why ? right ?

hba
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@kerribaberri ?

kerribaberri
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yeah, why? :P

kerribaberri
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i was wondering why there was a line in between

hba
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dw:1353960695933:dw
Here P(x)=polynomial of x
and
R(x)=remainder of x
So we seprate them ,Got it @kerribaberri ?

kerribaberri
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ohhh okay i get it @hba

hba
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We have been provided in the question that the remainder is 4
so
R(x)=4
got it ?

hba
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@kerribaberri ??

kerribaberri
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yup :)

kerribaberri
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yeah, i got it. :)

hba
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I can replace R(x) with p+k1+3
so
p+k+2=4
got it @kerribaberri ?

kerribaberri
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yes @hba

hba
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so p+k=42
p+k=2

hba
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Now lets solve the other one.dw:1353961284346:dw
Your turn @kerribaberri Do it i'll help you where you go wrong :)

kerribaberri
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so 2 goes on the left..

hba
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Yeah start doing it in the diag

kerribaberri
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k p 2 2 ? o_O

hba
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Do it in the diag lol

hba
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Do you see a pencil on my diag press it and start working

kerribaberri
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okayy

kerribaberri
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LOL did i pick the correct numbers though?

kerribaberri
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dw:1353961667693:dw

hba
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Where did 2 and +2 come from ?

kerribaberri
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dw:1353961803438:dw

kerribaberri
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i took the 2 from the equation and.. ohhhhhhh am i supposed to multiply 2 by 3?

kerribaberri
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ohhhh wait, i didn't realize the 3 and the 2 were exponents..

kerribaberri
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i thought they were base numbers

hba
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The equation in the first thing was
kx3 + px2  x + 3
so i got
k p 1 3
In the second case the equation iss
kx^3+px^2
so you should get
k p
right ?

hba
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dw:1353962035949:dwdw:1353962058098:dw

hba
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Got it ?

hba
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@kerribaberri Please concentrate Its easy.

kerribaberri
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okay i got it..

kerribaberri
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i see where the k and p are coming from but i don't see where the last two come from

hba
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dw:1353962174399:dw
Now continue

hba
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dw:1353962211804:dw

hba
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Got where the last two came from ?

kerribaberri
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yeah i see it there because there are numbers, but this one has none?

hba
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So you do not have to write anything.

hba
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dw:1353962420562:dw

kerribaberri
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ohhh, i never thought that was an option

hba
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Are you solving it now lol ?

kerribaberri
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r(x) = 21

hba
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@kerribaberri Please try.

hba
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@kerribaberri First solve it lol

hba
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dw:1353962559852:dw
bring the k down multiply it by 2

kerribaberri
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if there's no numbersdw:1353962609644:dw

hba
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What is wrong with you ?

hba
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The method is bring the k down multiply i by 2 so it will become 2k then it will go under p

hba
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@kerribaberri Please try to understand i feel like slamming my head in the wall.

hba
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@kerribaberri You there ?

kerribaberri
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i'll just ask someone else LOL

hba
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No i am showing you wait.

kerribaberri
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No you are not..

hba
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dw:1353963033373:dw

hba
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So,
R(x)=21
2x+p=21
got it ?

hba
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dw:1353963147883:dw

hba
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dw:1353963244019:dw

hba
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@kerribaberri got it ?