cupcake_queen
7a3=32a
solve for a



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Aditi_Singh
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Bring a's to one side and constants to the other.

ChristianGeek
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\[7a  3 = 3  2a\]\[7a  3 + 2a = 3  2a + 2a\]\[9a  3 = 3\]\[9a  3 + 3 = 3 + 3\]\[9a = 6\]\[\frac{9a}{9} = \frac{6}{9}\]\[a = \frac{6}{9}\]

cupcake_queen
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9a3=3

cupcake_queen
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oh ok

zordoloom
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BTW, 6/9 can be further simplified, but it looks good @ChristianGeek

ChristianGeek
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True, sorry...the final answer should be:
\[a = \frac{ 2 }{ 3 }\]