Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
poopsiedoodle
Group Title
For problems 1–5, simplify the expression. Answers written in decimal form will not be accepted. Each of these problems is worth 1 point.
"v/" is a radical by the way
___
1.v/96
______
2. 8 v/63x^5
___________
3. v/128x^5y^2
___
4. ^3v/32
________
5. ^3v/56x^14
 2 years ago
 2 years ago
poopsiedoodle Group Title
For problems 1–5, simplify the expression. Answers written in decimal form will not be accepted. Each of these problems is worth 1 point. "v/" is a radical by the way ___ 1.v/96 ______ 2. 8 v/63x^5 ___________ 3. v/128x^5y^2 ___ 4. ^3v/32 ________ 5. ^3v/56x^14
 2 years ago
 2 years ago

This Question is Closed

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
So, I need them in radical form.
 2 years ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.1
Factor everything first and then apply your radical rules... for example \[\sqrt[3]{x^3} = x\]
 2 years ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
Problem is that I have no idea what you're saying. ._.
 2 years ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.1
Ok for example \[\sqrt[8]{256x^4}\] becomes, if you factor \[\sqrt[8]{2^{8}x^4}\] which then becomes \[2\sqrt[8]{x^4}=2 x^{\frac{4}{8}}=2x^{1/2}=2\sqrt{2}\]
 2 years ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.1
This uses the idea that \[\sqrt[a]{x} = x^{1/a}\]
 2 years ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
just wondering, would you mind using bigger font? I can't see the exponents. To do that, put what you are saying in the curly braces in \(\huge\text{}\.) but take out the . at the end.
 2 years ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
the ^ means exponents. like, 2^3 is 2 cubed.
 2 years ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
\(\Large\text{But again, I have no idea how to do this.}\)
 2 years ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.1
is ^3v/56x^14 supposed to be \[\bigg(\sqrt{56x^{14}}\bigg)^3\] then?
 2 years ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
So, \(\huge\sqrt[8]{256x^4}\) turns into \(\huge\sqrt[8]{2^{8}x^4}\) which turns into \(\huge2\sqrt[8]{x^4}=2 x^{\frac{4}{8}}=2x^{1/2}=2\sqrt{2}\) But how? \(\huge\text{:}\)
 2 years ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.1
Sorry that should be \[2\sqrt{x}\]
 2 years ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
and no, it's supposed to be \[^{3}\sqrt{56x^{14}}\]
 2 years ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.1
ok the basic theorems that you need for these type of problems are that \[\sqrt[a]{x} = x^{\frac{1}{a}}\] So for example \[\large \sqrt[3]{x^{10}}\to x^{\frac{10}{3}}\to x^3x^{\frac{1}{3}}\to x^3\sqrt[3]{x}\]
 2 years ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
I understand the first half of your example equation, but not the second half.
 2 years ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.1
So any complicated radical you are given you can convert to exponents, use the rules of exponents shamelessly and then convert back to radical. So \[\large \sqrt[3]{56x^{14}}\to \sqrt[3]{(7)(8)x^{14}}\to 7^{1/3}8^{1/3}x^{14/3}\] This then becomes \[ 7^{1/3}8^{1/3}x^{14/3}\to 7^{1/3}(2^3)^{1/3}x^{12/3}x^{2/3}\] becomes \[7^{1/3}2x^{4}x^{2/3}\to 2x^4 7^{1/3}x^{1/3}\to 2x^4\sqrt[3]{7x}\]
 2 years ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
my brain is about to explode. e_o
 2 years ago

freewilly922 Group TitleBest ResponseYou've already chosen the best response.1
So you don't understand how \[x^{10/3} \to x^3x^{1/3}\]? This results from the fact that \[X^aX^b = X^{ab}\] and the reverse. So if you have \[x^{10/3}\] you have \[x^{9/3 + 1/3}\to x^{9/3}x^{1/3}\to x^3x^{1/3}\]
 2 years ago

poopsiedoodle Group TitleBest ResponseYou've already chosen the best response.1
again, might I suggest the larger font size? Maybe Large would be a good replacement for huge though.
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.