1. anonymous

2. anonymous

You have an angle, as well as hypotenuse and the opposite leg. Which function do you use when you have opposite and hypotenuse: sine, cosine, or tangent?

3. anonymous

this is geometry

4. anonymous

Okay, then you need to know the rules of a 30-60-90 triangle.

5. anonymous

Do you know how the three legs of a triangle relate?

6. anonymous

not reaally but kinda

7. anonymous

The ratio between short leg : long leg : hypotenuse is $$1 : \sqrt{3} : 2$$.

8. anonymous

Knowing that, you can use Pythagoras to solve for $$x$$. Being across from the 60º angle, would it be the long leg or the short leg?

9. anonymous

long?

10. anonymous

Right.

11. anonymous

so wouldnt the answer be B to this question?

12. anonymous

?

13. anonymous

That's what I get, yes, since $$\large x = \frac{\sqrt{3}}{2}(h)$$

14. anonymous

wouldnt it be B?

15. anonymous

As I said, yes. $\large x = \frac{\sqrt{3}}{2}(h) = \frac{16\sqrt{3}}{2} = 8\sqrt{3}$

16. anonymous

oh sorry their was a freezing problem! thanks so much:)

17. anonymous

No problem. It's being slow on my side, too. Have a good day. :)

18. anonymous

yes you to!!!:)