katlin95
please please help:) medals rewarded
find x
a. 8
b. 8sqrt3
c. 16 sqrt3
d. 1.8 sqrt3
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katlin95
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geoffb
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You have an angle, as well as hypotenuse and the opposite leg. Which function do you use when you have opposite and hypotenuse: sine, cosine, or tangent?
katlin95
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this is geometry
geoffb
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Okay, then you need to know the rules of a 30-60-90 triangle.
geoffb
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Do you know how the three legs of a triangle relate?
katlin95
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not reaally but kinda
geoffb
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The ratio between short leg : long leg : hypotenuse is \(1 : \sqrt{3} : 2\).
geoffb
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Knowing that, you can use Pythagoras to solve for \(x\). Being across from the 60º angle, would it be the long leg or the short leg?
katlin95
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long?
geoffb
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Right.
katlin95
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so wouldnt the answer be B to this question?
katlin95
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?
geoffb
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That's what I get, yes, since \(\large x = \frac{\sqrt{3}}{2}(h)\)
katlin95
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wouldnt it be B?
geoffb
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As I said, yes.
\[\large x = \frac{\sqrt{3}}{2}(h) = \frac{16\sqrt{3}}{2} = 8\sqrt{3}\]
katlin95
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oh sorry their was a freezing problem! thanks so much:)
geoffb
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No problem. It's being slow on my side, too. Have a good day. :)
katlin95
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yes you to!!!:)