Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

katlin95 Group Title

please please help:) medals rewarded find x a. 8 b. 8sqrt3 c. 16 sqrt3 d. 1.8 sqrt3

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. katlin95 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    • 2 years ago
    1 Attachment
  2. geoffb Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    You have an angle, as well as hypotenuse and the opposite leg. Which function do you use when you have opposite and hypotenuse: sine, cosine, or tangent?

    • 2 years ago
  3. katlin95 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    this is geometry

    • 2 years ago
  4. geoffb Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Okay, then you need to know the rules of a 30-60-90 triangle.

    • 2 years ago
  5. geoffb Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Do you know how the three legs of a triangle relate?

    • 2 years ago
  6. katlin95 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    not reaally but kinda

    • 2 years ago
  7. geoffb Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    The ratio between short leg : long leg : hypotenuse is \(1 : \sqrt{3} : 2\).

    • 2 years ago
  8. geoffb Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Knowing that, you can use Pythagoras to solve for \(x\). Being across from the 60º angle, would it be the long leg or the short leg?

    • 2 years ago
  9. katlin95 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    long?

    • 2 years ago
  10. geoffb Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Right.

    • 2 years ago
  11. katlin95 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    so wouldnt the answer be B to this question?

    • 2 years ago
  12. katlin95 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ?

    • 2 years ago
  13. geoffb Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    That's what I get, yes, since \(\large x = \frac{\sqrt{3}}{2}(h)\)

    • 2 years ago
  14. katlin95 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    wouldnt it be B?

    • 2 years ago
  15. geoffb Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    As I said, yes. \[\large x = \frac{\sqrt{3}}{2}(h) = \frac{16\sqrt{3}}{2} = 8\sqrt{3}\]

    • 2 years ago
  16. katlin95 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    oh sorry their was a freezing problem! thanks so much:)

    • 2 years ago
  17. geoffb Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    No problem. It's being slow on my side, too. Have a good day. :)

    • 2 years ago
  18. katlin95 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    yes you to!!!:)

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.