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anonymous
 3 years ago
please please help:) medals rewarded
find x
a. 8
b. 8sqrt3
c. 16 sqrt3
d. 1.8 sqrt3
anonymous
 3 years ago
please please help:) medals rewarded find x a. 8 b. 8sqrt3 c. 16 sqrt3 d. 1.8 sqrt3

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You have an angle, as well as hypotenuse and the opposite leg. Which function do you use when you have opposite and hypotenuse: sine, cosine, or tangent?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay, then you need to know the rules of a 306090 triangle.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do you know how the three legs of a triangle relate?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0not reaally but kinda

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The ratio between short leg : long leg : hypotenuse is \(1 : \sqrt{3} : 2\).

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Knowing that, you can use Pythagoras to solve for \(x\). Being across from the 60º angle, would it be the long leg or the short leg?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so wouldnt the answer be B to this question?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0That's what I get, yes, since \(\large x = \frac{\sqrt{3}}{2}(h)\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0As I said, yes. \[\large x = \frac{\sqrt{3}}{2}(h) = \frac{16\sqrt{3}}{2} = 8\sqrt{3}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh sorry their was a freezing problem! thanks so much:)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No problem. It's being slow on my side, too. Have a good day. :)
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