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please please help:) medals rewarded find x a. 8 b. 8sqrt3 c. 16 sqrt3 d. 1.8 sqrt3

Mathematics
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You have an angle, as well as hypotenuse and the opposite leg. Which function do you use when you have opposite and hypotenuse: sine, cosine, or tangent?
this is geometry

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Other answers:

Okay, then you need to know the rules of a 30-60-90 triangle.
Do you know how the three legs of a triangle relate?
not reaally but kinda
The ratio between short leg : long leg : hypotenuse is \(1 : \sqrt{3} : 2\).
Knowing that, you can use Pythagoras to solve for \(x\). Being across from the 60ยบ angle, would it be the long leg or the short leg?
long?
Right.
so wouldnt the answer be B to this question?
?
That's what I get, yes, since \(\large x = \frac{\sqrt{3}}{2}(h)\)
wouldnt it be B?
As I said, yes. \[\large x = \frac{\sqrt{3}}{2}(h) = \frac{16\sqrt{3}}{2} = 8\sqrt{3}\]
oh sorry their was a freezing problem! thanks so much:)
No problem. It's being slow on my side, too. Have a good day. :)
yes you to!!!:)

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