1. katlin95

2. geoffb

You have an angle, as well as hypotenuse and the opposite leg. Which function do you use when you have opposite and hypotenuse: sine, cosine, or tangent?

3. katlin95

this is geometry

4. geoffb

Okay, then you need to know the rules of a 30-60-90 triangle.

5. geoffb

Do you know how the three legs of a triangle relate?

6. katlin95

not reaally but kinda

7. geoffb

The ratio between short leg : long leg : hypotenuse is $$1 : \sqrt{3} : 2$$.

8. geoffb

Knowing that, you can use Pythagoras to solve for $$x$$. Being across from the 60º angle, would it be the long leg or the short leg?

9. katlin95

long?

10. geoffb

Right.

11. katlin95

so wouldnt the answer be B to this question?

12. katlin95

?

13. geoffb

That's what I get, yes, since $$\large x = \frac{\sqrt{3}}{2}(h)$$

14. katlin95

wouldnt it be B?

15. geoffb

As I said, yes. $\large x = \frac{\sqrt{3}}{2}(h) = \frac{16\sqrt{3}}{2} = 8\sqrt{3}$

16. katlin95

oh sorry their was a freezing problem! thanks so much:)

17. geoffb

No problem. It's being slow on my side, too. Have a good day. :)

18. katlin95

yes you to!!!:)