A community for students.
Here's the question you clicked on:
 0 viewing
henpen
 2 years ago
\[Ly=h(x)\]
f is the linear combination of all the functions that are L(function)=0, so that
\[Lf=0\]
And g is ONE OF the functions that do this:
\[Lg=h(x)\]
Why is the general (i.e. total and only (minus degrees of freedom for unknowable coefficients) is this the correct definition?) solution for y equal to this:
\[y=f+g\] I understand that it WORKS, but I've read in many places to stop here, as I've found the 'general' solution (whatever that really means) despite only using 1 out of potentially many g that do this \[L(function)=h(x)\]?
Does this rule only apply to a subset of differential equations, or are all other g not independent from out 1st g?
henpen
 2 years ago
\[Ly=h(x)\] f is the linear combination of all the functions that are L(function)=0, so that \[Lf=0\] And g is ONE OF the functions that do this: \[Lg=h(x)\] Why is the general (i.e. total and only (minus degrees of freedom for unknowable coefficients) is this the correct definition?) solution for y equal to this: \[y=f+g\] I understand that it WORKS, but I've read in many places to stop here, as I've found the 'general' solution (whatever that really means) despite only using 1 out of potentially many g that do this \[L(function)=h(x)\]? Does this rule only apply to a subset of differential equations, or are all other g not independent from out 1st g?

This Question is Open
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.