• anonymous
$Ly=h(x)$ f is the linear combination of all the functions that are L(function)=0, so that $Lf=0$ And g is ONE OF the functions that do this: $Lg=h(x)$ Why is the general (i.e. total and only (minus degrees of freedom for unknowable coefficients)- is this the correct definition?) solution for y equal to this: $y=f+g$ I understand that it WORKS, but I've read in many places to stop here, as I've found the 'general' solution (whatever that really means) despite only using 1 out of potentially many g that do this $L(function)=h(x)$? Does this rule only apply to a subset of differential equations, or are all other g not independent from out 1st g?
Calculus1
• Stacey Warren - Expert brainly.com
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SOLVED
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